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Colt1911 [192]
2 years ago
12

Which of the following choices is equivalent to the expression below 5^3+6^0

Mathematics
1 answer:
Nostrana [21]2 years ago
3 0
Since I do not know the options to this question,, I cannot answer it completely. I will help you solve the expression but I cannot determine which choice it is equivalent to,, so please keep that in mind. 
The first step to solving this expression is to evaluate the first power.
125 + 6^{0}
Any non zero expression that is raised to the power of 0 will equal 1,, so the expression will become the following:
125 + 1
Finally,, add the numbers together to get your final answer.
126
This means that whichever option equals 126 will be your correct answer. Again I apologize for not being able to answer this completely but I was not given the choices,, which made answering this difficult. 
Let me know if you have any further questions
:)
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Here is a sequence of numbers:
Anettt [7]

Triangular number sequnce

8 0
2 years ago
Please help me if you can ‼️
Karolina [17]

Answer:

y=14.5x+5

Step-by-step explanation:

Let

x ----> the number of tickets

y ----> the price of tickets

we have the ordered pairs

(4,63) and (6,92)

step 1

<em>Find the slope of the linear equation</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{92-63}{6-4}

m=\frac{29}{2}=\$14.5\ per\ ticket

step 2

Find the y-intercept or initial value of the linear equation

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope b is the y-intercept

we have

m=14.5

point\ (4,63)

substitute

63=14.5(4)+b

solve for b

b=63-14.5(4)

b=\$5

In this context the y-intercept is a one charge fee for the ticket service

The equation is equal to

y=14.5x+5

4 0
2 years ago
9.4+9.4-2.25+2.2-5.9+86.10+12.98-62.6
Luba_88 [7]

Answer:

49.33

Step-by-step explanation:

8 0
3 years ago
What is the first quartile of the set of data shown below?
____ [38]
The answer would be B 23
7 0
2 years ago
A self proclaimed psychic was tested for ESP. The psychic was presented with 200 cards face down and asked to determine if the c
swat32

Answer:

The 95% confidence interval would be given (0.172;0.288).  

We are confident at 95% that the true probability that the psychic correctly identifies the symbol on the card in a random trial is between (0.172;0.288).  

We can conclude that her random guessing would have got her correct 20% of the time. Since the confidence interval contains 0.2, she has no psychic powers, rather she just guessed it like normal people. Any person could have got it correct this many times.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the probability that the psychic correctly identifies the symbol on the card in a random trial

\hat p represent the estimated probability that the psychic correctly identifies the symbol on the card in a random trial

n=200 is the sample size required  

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the cases successful

\hat p=\frac{46}{200}=0.23 represent the estimated probability that the psychic correctly identifies the symbol on the card in a random trial

Confidence interval

The confidence interval for a proportion is given by this formula:

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

0.23 - 1.96 \sqrt{\frac{0.23(1-0.23)}{200}}=0.172  

0.23 + 1.96 \sqrt{\frac{0.23(1-0.23)}{200}}=0.288  

And the 95% confidence interval would be given (0.172;0.288).

We are confident at 95% that the true probability that the psychic correctly identifies the symbol on the card in a random trial is between (0.172;0.288).  

We can conclude that her random guessing would have got her correct 20% of the time. Since the confidence interval contains 0.2, she has no psychic powers, rather she just guessed it like normal people. Any person could have got it correct this many times.

6 0
3 years ago
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