A feasible region has vertices at (-1,3), (3,5), (4,-1), and (-1,-2) find the maximum and minimum values of each function

1 answer:

6 0

Answer: Choice D.
Max: f (-1,-2)=4; min:f(3,5)=-11

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Work Shown:

Plug in (x,y) = (-1,3)
f(x,y) = -2x-y
f(-1,3) = -2*(-1)-3
f(-1,3) = 2-3
f(-1,3) = -1
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Plug in (x,y) = (3,5)
f(x,y) = -2x-y
f(3,5) = -2*3-5
f(3,5) = -6-5
f(3,5) = -11
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Plug in (x,y) = (4,-1)
f(x,y) = -2x-y
f(4,-1) = -2*4-(-1)
f(4,-1) = -8+1
f(4,-1) = -7
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Plug in (x,y) = (-1,-2)
f(x,y) = -2x-y
f(-1,-2) = -2*(-1)-(-2)
f(-1,-2) = 2+2
f(-1,-2) = 4
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The four outputs are: -1, -11, -7, and 4

The largest output is 4 and that happens when (x,y) = (-1,-2)
So the max is f(x,y) = 4

The smallest output is -11 and that happens when (x,y) = (3,5)
So the min is f(x,y) = -11

This all points to choice D being the answer.

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