All categories

3 years ago

Which of the following takes place during a synthesis reaction?

Physics

1 answer:

11111nata11111 [884]3 years ago

8 0

The answer is C.
A is decomposition, B is Single Replacement, and D is Double Replacement

You might be interested in

I need help with this ?

olchik [2.2K]

Answer:

Frequency

Explanation:

Doesn't say how often he exercises

7 0

3 years ago

The density of Mercury is 1.36 × 10 by 4 Kgm - 3 at 0 degrees. Calculate its value at 100 degrees and at 22 degrees. Take cubic

Drupady [299]

a) Density at 100 degrees: $1.34\cdot 10^4 kg/m^3$

Explanation:

The density of mercury at 0 degrees is $d=1.36\cdot 10^4 kg/m^3$

Let's take 1 kg of mercury. Its volume at 0 degrees is

$V=\frac{m}{d}=\frac{1 kg}{1.36\cdot 10^4 kg/m^3}=7.35\cdot 10^{-5} m^3$

The formula to calculate the volumetric expansion of the mercury is:

$\Delta V= \alpha V \Delta T$

where

$\alpha=180\cdot 10^{-6} K^{-1}$ is the cubic expansivity of mercury

V is the initial volume

$\Delta T$ is the increase in temperature

In this part of the problem, $\Delta T=100 C-0 C=100 C=100 K$

So, the expansion is

$\Delta V= \alpha V \Delta T=(180\cdot 10^{-6} K^{-1})(7.35\cdot 10^{-5} m^3)(100 K)=1.3\cdot 10^{-6} m^3$

So, the new density is

$d'=\frac{m}{V+\Delta V}=\frac{1 kg}{7.35\cdot 10^{-5} m^3+1.3\cdot 10^{-6} m^3}=1.34\cdot 10^4 kg/m^3$

b) Density at 22 degrees: $1.355\cdot 10^4 kg/m^3$

We can apply the same formula we used before, the only difference here is that the increase in temperature is

$\Delta T=22 C-0 C=22 C=22 K$

And the volumetric expansion is

$\Delta V= \alpha V \Delta T=(180\cdot 10^{-6} K^{-1})(7.35\cdot 10^{-5} m^3)(22 K)=2.9\cdot 10^{-7} m^3$

So, the new density is

$d'=\frac{m}{V+\Delta V}=\frac{1 kg}{7.35\cdot 10^{-5} m^3+2.9\cdot 10^{-7} m^3}=1.355\cdot 10^4 kg/m^3$

8 0

3 years ago

g Light that is incident upon the eye is refracted several times before it reaches the retina. As light passes through the eye,

sertanlavr [38]

Answer

Explanation

:giác mạc

7 0

3 years ago

Which of the following measurements has one significant digit?

kow [346]

500m has 1 significant digit.

5 0

3 years ago

Read 2 more answers

If three boys are pushing on a 20 kg cart, each with 15 Newtons of force, and a horse is pulling the cart in the opposite direct

sertanlavr [38]

The acceleration of the cart is zero

Explanation:

There are 4 forces acting on the cart:

- The 3 forces of F=15 N each, applied forward by three boys

- The force of F'=45 N applied backward by the horse

So we can write Newton's second law of motion as:

$3F-F' = ma$

where

m is the mass of the cart

a is its acceleration

Here we have

m = 20 kg

So we can solve the equation for a, the acceleration of the cart:

$a=\frac{3F-F'}{m}=\frac{3(15)-45}{20}=0$

This means that the acceleration of the cart is zero, because the force applied by the horse perfectly balance the forces applied by the three boys.

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

7 0

3 years ago