Question

A student is bicycling north along Main Street to school. Another student is timing the bicycling student in order to determine the average velocity. The bicycling student is 450 m away when the timer starts, and is 200 m away when the timer stops. If the student traveled the distance in 60 seconds, what is the students average velocity?

Answer 1

The average velocity is -4.17 m/s

Explanation:

The average velocity of a body is given by:

$v=\frac{d}{t}$

where

d is the displacement of the body

t is the time elapsed

For the student in this problem, we have:

Initial position: $x_i = 450 m$

Final position: $x_f = 200 m$

So the displacement is

$d=x_f -x_i = 200 - 450 = -250 m$

The time elapsed is

t = 60 s

Therefore, the average velocity is

$v=\frac{-250}{60}=-4.17 m/s$

Where the negative sign means the student is moving towards the origin.

Learn more about average speed and velocity:

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