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Katarina [22]
3 years ago
10

If three boys are pushing on a 20 kg cart, each with 15 Newtons of force, and a horse is pulling the cart in the opposite direct

ion with 45 Newtons of force, what is the acceleration of the cart?
Physics
1 answer:
sertanlavr [38]3 years ago
7 0

The acceleration of the cart is zero

Explanation:

There are 4 forces acting on the cart:

- The 3 forces of F=15 N each, applied forward by three boys

- The force of F'=45 N applied backward by the horse

So we can write Newton's second law of motion as:

3F-F' = ma

where

m is the mass of the cart

a is its acceleration

Here we have

m = 20 kg

So we can solve the equation for a, the acceleration of the cart:

a=\frac{3F-F'}{m}=\frac{3(15)-45}{20}=0

This means that the acceleration of the cart is zero, because the force applied by the horse perfectly balance the forces applied by the three boys.

Learn more about acceleration and forces:

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#LearnwithBrainly

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Current and voltage on each resistor:

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Explanation:

In order to solve the circuit, we first have to find the equivalent resistance of the whole circuit, then the total current, and then we can proceed finding the current and the voltage for each resistor.

We start by calculating the equivalent resistance of resistors 2 and 3, which are in parallel:

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This resistor is in series with resistor 4, so:

R_{234}=R_{23}+R_4=0.833+2.0=2.833\Omega

This resistor is in parallel with resistor 5, therefore:

R_{2345}=\frac{R_{234}R_5}{R_{234}+R_5}=\frac{(2.833)(2.0)}{2.833+2.0}=1.172\Omega

This resistor is in series with resistor 7, so:

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