M(NH₃)=51g, n(NH₃)=m/M=51g÷17g/mol(14+3×1)=3mol
N(NH₃)=n×Na(Avogadro number)=3mol×6·10²³1/mol=18×10²³ molecules
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Examining the sample, we find that each 3 moles of carbon combine with 8 moles of hydrogen.
The ration is thus 3:8
Based on this, we can calculate the number of hydrogen moles in the sample as follows:
number of hydrogen moles = <span>15.7 x 8 ∕ 3 = 41.8667 moles
Total number of moles in the sample = 15.7 + 41.8667 = 57.5667 moles</span>