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jekas [21]
2 years ago
10

10 cm 10 cm 8 cm 6cm Find the area of trapezoid ABCD.​

Mathematics
1 answer:
butalik [34]2 years ago
8 0

Answer:

need more context

Step-by-step explanation:

Trapezoid area formula:

A=(base¹+base²/2)×height

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PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!
levacccp [35]
The answer is 20x-21y+14
7 0
2 years ago
Read 2 more answers
Using the quadratic formula to solve x? + 20 = 2x, what are the values of x?
Sergio [31]
I am not sure if the “+” was supposed to go there or if that was just a typo, so I do apologize if this is wrong... but if it doesn’t belong in the equation at all, 20 = 2X is a fairly simply multiplication problem. You are to divide both sides by the 2 and you should get X = 10, because 2 goes into 20, 10 times; and the 2 goes into 2 only once, therefore the 2 now gets cancelled out.

Answer: 20 divided by 2 = 2x divided by 2 is now 10 = X.

Really hope this helps you, have a good day :)
6 0
3 years ago
Does the point (–3, 4) satisfy the equation y = –2x + 5? Yes Or No
Mekhanik [1.2K]

Answer:

No

Step-by-step explanation:

y = -2x + 5

4 = -2(-3) + 5 - Substitute both x and y

4 = 6 + 5 - Simplify

4 ≠ 11

Hence, no, (-3, 4) doesn't statify the equation y = -2x + 5

6 0
2 years ago
Subtract and simplify. Show work please!
ra1l [238]

1) Final expression: +7y^2-6y-17

2) Final expression: 21x^3-46x^2+59x-30

Step-by-step explanation:

1)

The first expression is

(-2y^2-11y-7)-(-9y^2-5y+10)

First, we remove the 2nd bracket by changing the sign of all the terms inside:

-2y^2-11y-7-+9y^2+5y-10

Now we group the terms with same degree together:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)

Now we solve the expression in each brackets:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)=\\+7y^2-6y-17

So, this is the final expression.

2)

The second expression is

(7x-6)(3x^2-4x+5)

We apply the distributive property, so we rewrite the expression as follows:

(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)

Solving both brackets,

7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30

Now we group terms of same degree together:

21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30

And solving each bracket,

21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

3 0
3 years ago
Half an hour after leaving her house Beverly was 20 miles from home. At this point she merged onto the highway and was traveling
N76 [4]

Answer:

1. 45.71 miles

2. 10 miles

3. 89.43 miles

4. 0.79 hr

5. 0.025 hr

Step-by-step explanation:

speed = distance/time

After 4 hrs Beverly was 200 miles from home , however she had spent 0.5hr travelling for 20 miles prior to getting to the highway.

Therefore;

Constant speed before Highway = 20/0.5 = 40 miles/hr

Constant speed at Highway = \frac{(200-20)}{(4-0.5)} = 51.43 miles/hr

1. in 1 hr beverly will have travelled;

⇒ (20 miles in 0.5 hr ) + (0.5 hr  at speed 51.43 miles/hr)

⇒ 20 + (0.5 x 51.43) = 45.71 miles

2. In 0.25 hr beverly had not reached the highway

⇒ distance = speed x time

⇒ distance = 40 x 0.25 = 10 miles

3. in 1.85 hrs beverly will have travvelld;

⇒ (20 miles in 0.5 hr ) + (1.35 hr at speed 51.43 miles/hr)

⇒ 20 + 69.43 = 89.43 miles

4. Time taken to get to 35 miles

⇒ (20 miles in 0.5 hr ) + (15 miles  at speed 51.43 miles/hr)

⇒ 0.5hr + (15/51.43) hr = 0.79 hr

5. Time taken to travel 1 mile

 ⇒ time = distance / speed = 1 mile  / 40 miles/hr

⇒ time = 0.025 hr

8 0
3 years ago
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