To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b

The dimension of the 4 rectangles are:

a. length: 4x and width: 4

b. length: 11 and width: x

c. length: 2 and width: 8x

d. length: 16x and width: 1

The area of a rectangle is:

$Area = Length \times Width$

Rectangle (a)

$Area = 4x \times 4$

$Area = 16x$

Rectangle (b)

$Area = 11 \times x$

$Area = 11x$

Rectangle (c)

$Area = 2 \times 8x$

$Area = 16x$

Rectangle (d)

$Area = 16x \times 1$

$Area = 16x$

Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.

Hence, the rectangle with a different area is rectangle (b).

Read more about areas of rectangles at:

brainly.com/question/14383947

7 0

2 years ago

ioda

The first one is B4:25

6 0

3 years ago

Read 2 more answers

3x + 5 and x=2, im having trouble understanding how im suppose to do this

velikii [3]

3x + 5 (first plug in 2 for x )

3(2) + 5 =
6 + 5 = 11

Hope this helps . Give brainliest

6 0

2 years ago

There so a fraction that is equivalent to 25/30. The difference between the denominator and the numerator is 1. The sum of the d

fenix001 [56]

The fraction is 5/6
(difference is 1 and 5+6=11)

4 0

3 years ago

Read 2 more answers