Answer:
6000
Step-by-step explanation:
Answer:
Both the boats will closet together at 2:21:36 pm.
Step-by-step explanation:
Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).
Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),
Formula : d=v*t
at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)
the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)
Formula : D=
⇒ 
Now let 
∵ 
⇒ t= 450/1250
⇒ t= .36 hours
⇒ = 21 min 36 sec
Since F"(t)=0,
∴ This time gives us a minimum.
Thus, The two boats will closet together at 2:21:36 pm.
The y-in is -6
The x- in is -1 and -6
The vertex is (-3.5,-6.25)
The axis is -3.5
Step-by-step explanation:








J/4 - 8 < 4
<u> + 8 + 8 </u> *add 8 to both sides to cancel -8.
j/4 < 12
<u>*4/1 *4/1 </u> *multiply 4/1 to both sides to cancel 1/4
j < 48
j should be less than 48 to make the inequality true.
example: j = 47
j/4 - 8 < 4
47/4 - 8 < 4
11.75 - 8 < 4
3.75 < 4
Any number below 48 will end up with an answer less than 4. if j is 48 and above, the inequality is false because the answer arrived at will be equal to or greater than 4.