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3 years ago

What value of x satisfies the equation 3x/7+5/7=4/7

Mathematics

1 answer:

Nana76 [90]3 years ago

3 0

You can multiply everything by 7 to make things simpler.
3x + 5 = 4
3x = -1
x = -1/3

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which rate can you set 7 miles over 1 hour equal to in order to find the distance traveled in 49 hours at 7 miles per hour

IrinaVladis [17]

Answer:

Step-by-step explanation:

time = 49 hours

speed = 7 miles/hour

speed = distance / time

∴ distance = speed × time

= 7 × 49

= 343 miles

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3 years ago

Please answer this correctly as soon as possible I want genius or expert people to answer this correctly

Ede4ka [16]

6/54 times because there are 9 marbles and the orange marble is 1 out of those 9 marbles. If you multiply 6*9= 54 then you notice there is a 6/54 chance of picking any 1 marble out of the 54 times that you decide to pick marbles.

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3 years ago

6. A piece of cardboard is cut in an L-shape as

andrey2020 [161]

Answer: a= 120

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2 years ago

In the figure below, m∠1 = x and m∠2 = x - 4. Which statement could be used to prove that x = 47?

dangina [55]

The answer is C) m∠1 + m∠2 = 90

Explanation: So ∠1 is x and ∠2 is x-4

Basically you know than ∠3 is 90° ... And a straight line is 180° .. So technically we can just find out 180-90 is 90(the other angle 1 + 2).

To get 90° we'll add ∠1 and ∠2 in other ways, like technical thinking-

So you already know adding ∠1 and ∠2 is 90°. So ∠1 + ∠2 = 90°

In other words you can say m∠1 + m∠2 = 90

3 0

2 years ago

Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.

VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let $\mu$ = mean commute time in the U.S..

So, Null Hypothesis, $H_0$ : $\mu \geq$ 30 minutes {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, $H_A$ : $\mu$ < 30 minutes {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean commute time = 27.6 minutes

s = sample standard deviation = 19.6 minutes

n = sample of people from the 2000 U.S. Census = 500

So, the test statistics = $\frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }$ ~ $t_4_9_9$

= -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0

3 years ago