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Paraphin [41]
4 years ago
13

Determine the rate of a reaction that follows the rate law rate = k a m b i where

Chemistry
1 answer:
ikadub [295]4 years ago
6 0
(missing part of your question):
when we have K = 1 x 10^-2 and [A] = 2 M & [B] = 3M & m= 2 & i = 1
So when the rate = K[A]^m [B]^i
and when we have m + i = 3 so the order of this reaction is 3 So the unit of K is L^2.mol^-2S^-1
So by substitution:
∴ the rate = (1x 10 ^-2 L^-2.mol^-2S^-1)*(2 mol.L^-1)^2*(3mol.L^-1)
                 = 0.12 mol.L^-1.S^-1
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175 ml of a 1.6 m solution of kcl is diluted to a new volume of 1.0 l. what is the new concentration of the solution? (3 points)
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175 ml of a 1.6 m solution of KCl is diluted to a new volume of 1.0 L. The new concentration of the solution is 0.28 m KCl.

Hence, Option (B) is correct answer.

<h3>What is Concentration ?</h3>

Concentration is defined as the measure of how much substance there is mixed with another substance.

<h3>How to find the concentration ?</h3>

To find the concentration use the dilution formula

C₁V₁ = C₂V₂

where,

C₁ = Concentration of starting solution

C₂ = Concentration of final solution

V₁ = Volume of the starting solution

V₂ = Volume of the final solution

Now put the values in above formula we get

C₁V₁ = C₂V₂

1.6 × 0.175 = C₂ × 1.0

0.28 = C₂ × 1.0

C₂ = 0.28

Thus from the above conclusion we can say that 175 ml of a 1.6 m solution of KCl is diluted to a new volume of 1.0 L. The new concentration of the solution is 0.28 m KCl.

Hence, Option (B) is correct answer.

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