Answer : The pH of the resulting solution is 4.6
Explanation : Given,
Activity coefficient for acetic acid = 1.000
Activity coefficient for acetate ion = 0.775
Ionic strength = 0.10 M
To calculate the pH of resulting solution we are using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
Now put all the given values in this expression, we get:
Thus, the pH of the resulting solution is 4.6
Answer:
a. 2nd order reaction.
b. The first step is the slow step.
Explanation:
r = k[NO][Cl₂]
a. The reaction is first-order in [NO] and first-order in [Cl₂], so it is second-order overall.
b. The first step is the slow step, because it predicts the correct rate law.
c. is wrong. Doubling [NO] would double the rate, because the reaction is first-order in [NO].
d. is wrong. Cutting [Cl₂] in half would halve the rate, because the reaction is first-order in [Cl₂].
e. is wrong. The molecularity is two, because two particles are colliding.
f. is wrong. Both steps are bimolecular.
Answer:
a. ΔH⁸ = -1420 kJ/mol b. ΔH⁸ = -1144.84 kJ/mol
Explanation:
a.
C₂H₄ (g) + 3 O₂ (g) ------------------------ 4 CO₂ (g) + 2 H₂O (l) ΔH⁸ = ?
ΔH⁸f kJmol 52.47 0 -399.5 -285.83
ΔH⁸ = 2(-399.5) + 2 (-285.83) - (52.47)
ΔH⁸ = -1420 kJ/mol
b.
H₂S (g) + 3 O₂ (g) ---------------------- 2 H₂O (l) + 2 SO₂ (g)
ΔH⁸f kJmol -20.50 0 -285.83 -296.84
ΔH⁸ = 2(-285.83) + 2 (-296.84) - (-20.50)
ΔH⁸ = -1144.84 kJ/mol
<span>Amino acids which are known to be linked by peptide bonds they form polypeptide chains.
Proteins are linear polymers are formed by way of linking an a-carboxy group of one amino acid to a-amino of different amino acids which have peptide bond. The formation which results from two amino acids which result in a loss of a water molecule. The best process of the reaction is hydrolysis.</span>
