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CaHeK987 [17]
3 years ago
14

Can someone help, like I need an answer now ಥ‿ಥ​

Chemistry
1 answer:
Viefleur [7K]3 years ago
8 0

Answer:

cell - basic unit of structure and function of all living things

tissue - a group of cells that work together to perform a common function

organ - a group of tissues that work together to perform a common function

organ system - group of organs that work together to perform a common function

Explanation:

What you have there is the biological level of organization. It is how living things are organized from the simplest to the most complex. Each level makes up another level.

As you can see in your exercise, the basic unit of life is the cell and cells make up tissues, while tissues make up organs and so forth. There are higher levels of organizations passed organ system.

Cell - tissue - organ - organ system - organism - population - community - ecosystem - biosphere

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Which of the following best describes a metal? Brittle, shiny, and solid Brittle, dull, and low density Malleable, shiny, and ab
yanalaym [24]

Answer : The correct option is, Malleable, shiny, and able to conduct heat or electricity.

Explanation:

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Non-metals : Non-metals are the elements which can easily gain electrons and form an anion.

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8 0
2 years ago
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In order to prepare 50.0 mL of 0.100 M NaOH you will add _____ mL of 1.00 M NaOH to _____ mL of water
FinnZ [79.3K]

The question requires us to complete the sentence regarding the preparation of a more dilute NaOH solution (0.100 M, 50.0 mL) from a more concentrated NaOH solution (1.00 M).

Analyzing the blank spaces that we need to fill in the sentence, we can see that we must provide the volume of the more concentrated solution and the volume of water necessary to prepare the solution.

We can use the following equation to calculate the volume of more concentrated solution required:

\begin{gathered} C_1\times V_1=C_2\times V_2 \\ V_1=\frac{C_2\times V_2}{C_1} \end{gathered}

where C1 is the concentration of the initial solution (C1 = 1.00 M), V1 is the volume required of the inital solution (that we'll calculate), C2 is the concentration of the final solution (C2 = 0.100 M) and V2 is the volume of the final solution (V2 = 50.0 mL).

Applying the values given by the question to the equation above, we'll have:

\begin{gathered} V_1=\frac{C_2\times V_2}{C_1} \\ V_1=\frac{0.100M_{}\times50.0mL_{}}{1.00M_{}}=5.00mL \end{gathered}

Thus, we would need 5.00 mL of the more concentrated solution.

Since the volume of the final solution is 50.0 mL and it corresponds to the volume of initial solution + volume of water, we can calculate the volume of water necessary as:

\begin{gathered} \text{final volume = volume of initial solution + volume of water} \\ 50.0mL=5.00mL\text{ + volume of water} \\ \text{volume of water = 45.0 mL} \end{gathered}

Thus, we would need 45.0 mL of water to prepare the solution.

Therefore, we can complete the sentence given as:

<em>"In order to prepare 50.0 mL of 0.100 M NaOH you will add </em>5.00 mL<em> of 1.00 M NaOH to </em>45.0 mL<em> of water"</em>

5 0
10 months ago
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