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barxatty [35]
3 years ago
15

Why do large area's of water change how the wind blows?

Chemistry
2 answers:
sp2606 [1]3 years ago
5 0

Answer:

C

water changes temperature slowly i believe C is your anwser

ser-zykov [4K]3 years ago
5 0

Answer:

c

water changes temperature slowly

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What is the mass of 3.6 x 1024 atoms of Zinc (Zn)?
AlladinOne [14]
Answer is: mass od zinc is 392,28 g.
N(Zn) = 3,6·10²⁴.
n(Zn) = N(Zn) ÷ Na.
n(Zn) =  3,6·10²⁴ ÷ 6·10²³ 1/mol.
n(Zn) = 6 mol.
m(Zn) = n(Zn) · M(Zn).
m(Zn) = 6 mol · 65,38 g/mol.
m(Zn) = 392,28 g.
Na - Avogadro number.
n - amount of substance.
M - molar mass.
7 0
3 years ago
1. Balance the chemical reaction for the production of hydrogen cyanide: __ NH3(g) + __ O2(g) + __ CH4(g) → __ HCN(g) + __ H2O(g
Solnce55 [7]
<span>2 NH</span>₃<span> + 3 O</span>₂<span> + 2 CH</span>₄<span> </span>⇒<span> 2 HCN + 6 H</span>₂<span>O
2mol                     :           2mol
34g                       :           54g
25,1g                    :           x

x = (25,1g * 54g) / 34g </span>≈ 39,9g<span>
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5 0
3 years ago
What type of wave requires a medium to transfer energy?
Liula [17]
YYe the answer is mechanical
5 0
3 years ago
Read 2 more answers
Two well-known complex ions containing ni are [ni(h2o)6]2+, which is green, and [ni(en)3]2+, which is purple. which one of these
Julli [10]
For [Ni(en)³]²⁺ which is purple, the crystal field splitting energy is greater than the complex ion, [Ni(H₂O)₆]²⁺ which is green in color.
When a Lewis base id attached to the metal ion by covalent bond, then the complex ion is formed and when these complex ions are present with other ions of opposite charge or neutral charge, they will make complex compounds.
7 0
3 years ago
The pressure of a sample of helium in a 200. ml container is 2.0 atm. If the helium is compressed to a pressure of 40. atm witho
Crank

Answer:

V_2=10mL

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to solve this problem by using the Boyle's law as an inversely proportional relationship between pressure and volume:

P_2V_2=P_1V_1

In such a way, we solve for the final volume, V2, and plug in the initial volume and pressure and final pressure to obtain:

V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{2.0atm*200.mL}{40.atm}\\\\V_2=10mL

Regards!

5 0
3 years ago
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