Answer:
<em>Find the probability of success in a single trial and then think about the nature of the problem (when do we stop). </em>
Step-by-step explanation:
Observe that in the single trial, we have (8 4) possibilities of choosing our set of balls. If we have chosen two white balls and two black balls, the probability of doing that is simply
p=(4 2)*(4 2)/(8 4)
This is well know Hyper geometric distribution. Now, define random variable X that marks the number of trials that have been needed to obtain the right combination (two white and two black balls). From the nature of the problem, observe that X has Geometric distribution with parameter p that has been calculated above. Hence
P(X = n) = (1— p)^n-1 *( p )
<em>Find the probability of success in a single trial and then think about the nature of the problem (when do we stop). </em>
154 divided by 7 i think
so 22 students per class
Mr. Jones has 22 students per class
RZ and RT are equal (or congruent).
Answer:
3
Step-by-step explanation:
5(x-1)-2
5(2-1)-2
5×1-2
5-2
3
Hope this helps you :)
please mark brainliest
Given:
The equation is:
It cuts the x-axis and y- axis at the point A and B respectively.
The area of ∆AOB =12 sq.units.
To find:
The value of <em>k</em>.
Solution:
We have,
Substituting 
to find the y-intercept.
Substituting 
to find the x-intercept.
Area of a triangle is:
The height of the ∆AOB is 
because distance cannot be negative and the base of the ∆AOB is 
. So, the area of the ∆AOB is:
It is given that, the area of ∆AOB = 12 sq.units.
Therefore, the value of k is either 24 or -24.
