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3 years ago

An object is held at rest and allowed to drop How far does the object fall in 3.3 seconds?

1 answer:

6 0

After x seconds, an object will fall $\frac{1}{2}at^2$ where a is acceleration due to gravity and t is time

so when t=3.3
the distance it will fall is $(\frac{1}{2})(9.8\frac{m}{s^2})(3.3m)^2$ =53.361m
it will fal 53.361 meters

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Show that the entire Paschen series is in the infrared part of the spectrum. To do this, you only need to calculate the shortest

mr_godi [17]

Answer and Explanation:

The computation of the shortest wavelength in the series is shown below:-

$\frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )$

Where

$\lambda$ represents wavelength

R represents Rydberg's constant

$n_f$ represents Final energy states

and $n_i$ represents initial energy states

Now Substitute is

$1.097\times 10^7\ m^{-1}\ for\ R, \infty for\ n_i,\ 3 for\ n_i,\\\\\ \frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )$

now we will put the values into the above formula

$= 1.097\times 10^7 m^{-1}(\frac{1}{3^2} - \frac{1}{\infty^2} )\\\\ = 1.097\times10^7\ m^{-1} (\frac{1}{9} )$

$= 1218888.889 m^{-1}$

Now we will rewrite the answer in the term of $\lambda$

$\lambda = \frac{1}{1218888.889} m\\\\ = 0.82\times 10^{-6} m$

So, the whole Paschen series is in the part of the spectrum.

8 0

4 years ago

Tubby and his twin brother Libby have a combined mass of 200 kg and are zooming along in a 100 kg amusement park bumper car at 1

harkovskaia [24]

Answer: 14.1 m/s

Explanation:

We can solve this with the Conservation of Linear Momentum principle, which states the initial momentum $p_{i}$ (before the elastic collision) must be equal to the final momentum $p_{f}$ (after the elastic collision):

$p_{i}=p_{f}$ (1)

Being:

$p_{i}=m_{1}V_{i} + m_{2}U_{i}$

$p_{f}=m_{1}V_{f} + m_{2}U_{f}$

Where:

$m_{1}=200 kg +100 kg=300 kg$ is the combined mass of Tubby and Libby with the car

$V_{i}=10 m/s$ is the velocity of Tubby and Libby with the car before the collision

$m_{2}=25 kg + 100 kg=125 kg$ is the combined mass of Flubby with its car

$U_{i}=0 m/s$ is the velocity of Flubby with the car before the collision

$V_{f}=4.12 m/s$ is the velocity of Tubby and Libby with the car after the collision

$U_{f}$ is the velocity of Flubby with the car after the collision

So, we have the following:

$m_{1}V_{i} + m_{2}U_{i}=m_{1}V_{f} + m_{2}U_{f}$ (2)

Finding $U_{f}$ :

$U_{f}=\frac{m_{1}(V_{i}-V_{f})}{m_{2}}$ (3)

$U_{f}=\frac{300 kg(10 m/s-4.12 m/s)}{125 kg}$ (4)

Finally:

$U_{f}=14.1 m/s$

8 0

3 years ago

What is the energy in the spark produced by discharging the second capacitor? 1. The same as the discharge spark of the first ca

Nastasia [14]

Complete Question

The two isolated parallel plate capacitors be- low, one with plate separation d and the other with D > d, have the same plate area A and

are given the same charge Q.

What is the energy in the spark produced by discharging the second capacitor?

1. The same as the discharge spark of the first capacitor

2. More energetic than the discharge spark of the first capacitor

3. Less energetic than the discharge spark of the first capacitor

Answer:

The correct option is 2

Explanation:

The formula for the energy stored in the capacitor is

$U = \frac{Q^2}{2C}$

And generally the formula for finding the capacitance of a capacitor is

$C = \frac{\epsilon_oA}{d}$

We can denote the capacitance of the first capacitor as $C_1 = \frac{\epsilon_oA}{d}$

and denote the capacitance of the second capacitor as $C_2 = \frac{\epsilon_oA}{D}$

Looking at this formula we can see that C varies inversely with d

as D > d it means that $C_1 > C_2$

Since the charge is constant

$U\ \alpha\ \frac{1}{C}$ i.e U varies inversely with C

So $C_1 > C_2$ => $U_2 >U_1$

This means that the energy of spark would be more for capacitor two compared to capacitor one

The correct option is 2

6 0

3 years ago

Shondra takes notes in class.

sdas [7]

Answer:

I beileve its A because energy is what gives the ability to do work

Explanation:

4 0

3 years ago

Use the drop-down menus to complete the statements. are pure substances that cannot be broken down into a simpler form. are unit

Vika [28.1K]

Answer: Please see below

Explanation:

Are pure substances that cannot be broken down into a simpler form---- Element

are units of two or more atoms---- Molecule

are the smallest possible particles of an element---- an Atom

are pure substances made of two or more atoms of different elements---- Compound

An atom is the smallest unit of matter that consists of protons, neutrons and electrons. Eg the element, helium, contains atoms with two protons in the nucleus.

Eg of element, we have carbon, hydrogen, helium

Eg of a compound--- Ammonia

Eg of a molecule-----H2O (water),C6H12O6 (glucose)

3 0

3 years ago