Please help with my geology hw

A 44 kg block lies on a horizontal frictionless surface. A horizontal force of 110 N is applied to the block. (a) Determine the

Oksana_A [137]

44k jkjk know the answer

8 0

4 years ago

Miss Piggy is exercising her vocal chords by matching the frequency f = 686 Hz of her speaker 4 m away. Where should Kermit sit

monitta

Answer:

$z=\frac{2n+1}{8}$ for $n=0,1,2,3,...,15$

Where z=0 m is the position of Miss Piggy and z=4 m is the position of the speaker.

Explanation:

Assuming that Miss Piggy emits a sound wave that is in phase with the speaker, and that z=0 is the position of Miss Piggy and z=4 is the position of the speaker, we would have a superposition of two traveling sound waves. Furthermore let's assume that both waves have the same amplitude. The total resulting wave will be given by:

$\psi(t,z)=A\cos(\omega t-kz)+A\cos(\omega t +kz)$ where $\omega$ is the angular frequency of the traveling wave and $k$ is the wave number defined as $k=\frac{2\pi}{\lambda}$ . $\lambda$ is the wavelength of both traveling waves (they have the same wavelength because they have the same frequency). $\lambda=\frac{v}{f}$ where v is the speed of sound.

By using the trigonometric identity $2\cos(A)\cos(B)=\cos(A+B)+\cos(A-B)$ we can rewrite $\psi (t,z)$ as

$\psi (t,z)=2A\cos(\omega t)\cos(kz)$ .

In order for the resulting wave to have maximum destructive interference, that is to be zero for any time t, we need to have

$\cos(kz)=0$

$\implies kz=(2n+1)\cdot \frac{\pi}{2}\implies z=(2n+1)\frac{\pi}{2k}=(2n+1)\frac{\pi}{2}\frac{\lambda}{2\pi}=(2n+1)\cdot \frac{\lambda}{4}$

$\implies z=(2n+1)\cdot\frac{v}{4f}=\frac{2n+1}{8}$

3 0

3 years ago

The waste product of photosynthesis is:

zalisa [80]

Answer:

The waste product of photosynthesis is oxygen

6 0

3 years ago

a car with a mass of 1.2×10^3 kilograms is moving at a speed of 18 meters/second. it is hit by a truck from behind and it's spee

garik1379 [7]

I = Delta p

I = Impulse
Delta p = Momentum variation

Delta p = pf - po

Pf = Final momentum
Po = Initial momentum

p = m x v

M = Mass
V = Velocity

Delta p = (m x Vf) - (m x Vo)

I = 1.2 x 10^3 x 20 - 12 x 10^2 x 18
I = 2.4 x 10^4 - 216 x 10^2
I = 2.4 x 10^4 - 2.16 x 10^4
I = 0.24 x 10^4
I = 24 x 10^2 Newtons x seconds (N x s)

Answer: The value of impulse is 24 x 10^2 Newtons x seconds (N x s).

8 0

3 years ago

What happens when an electron returns to its ground state from its excited state

Norma-Jean [14]

Answer: Energy is released by the electron in the form of light

Explanation:

Let's start by explaining that each atom in its natural state has a specific structure of its energy levels. Where the lowest energy level is called the ground state.

So, when an atom is in its ground state, its electrons fill the lower energy orbitals completely before they begin to occupy higher energy orbitals.

Then, when an atom is excited, it means that it has left its ground state (in which each electron occupies its place in its orbit, around the nucleus), when this happens some electron jumps out of the orbit it occupied in its fundamental state to an outer orbit, further away from the nucleus and then return to the ground state, emitting in the form of light the energy received.

To understand it better:

An excited electron is an unstable electron, and when passing from one orbit to another, it produces light of a specific wavelength (color) that depends on the amount of energy the electron loses.

5 0

4 years ago