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Bad White [126]
3 years ago
10

How to calculate kinetic energy of a projectile at the highest point of a projectile?

Physics
2 answers:
Marianna [84]3 years ago
6 0
Kinetic energy is half the product of the mass and the square velocity and at highest point the velocity is 0 thus the kinetic energy is 0 J
DIA [1.3K]3 years ago
3 0

For a projectile  the total energy is equal to the kinetic energy that is  1/2 mv and the  the potential energy mgh that add. Initially the total energy is all kinetic energy at the highest point the energy is all potential.so kinetic energy  at that point is 0.
hope it helps
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Two objects with masses of 2.75 kg and 4.45 kg are connected by a light string that passes over a light frictionless pulley to f
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Answer:

Explanation:

F = ma

4.45g - 2.75g = (4.45 + 2.75)a

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a)

T = 2.75(9.81 + 2.32) = 33.3 N

or

T = 4.45(9.81 - 2.32) = 33.3 N

b) 2.32 m/s² upward for 2.75 kg mass

    2.32 m/s² downward for 4.45 kg mass

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4 0
2 years ago
Engineering solutions use scientific laws to predict behaviors of objects in certain situations. Will used Newton's Laws of Moti
Alinara [238K]

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3 years ago
on a very muddy football field, a 120 kg linebacker tackles an 75 kg halfback. immediately before the collision, the linebacker
DIA [1.3K]
<u>Momentum</u> 
- a vector quantity; has both magnitude and direction
- has the same direction as object's velocity
- can be represented by components x & y.

Find linebacker momentum given m₁ = 120kg, v₁ = 8.6 m/s north
P₁ = m₁v₁
P₁ = (120)(8.6)
[ P₁ = 1032 kg·m/s ] = y-component, linebacker momentum

Find halfback momentum given m₂ = 75kg, v₂ = 7.4 m/s east
P₂ = m₂v₂
P₂ = (75)(7.4)
[ P₂ = 555 kg·m/s ] = x-component, halfback momentum

Find total momentum using x and y components.
P = √(P₁)² + (P₂)²
P = √(1032)² + (555)²
[[ P = 1171.77 kg·m/s ]] = magnitude 

!! Finally, to find the magnitude of velocity, take the divide magnitude of momentum by the total mass of the players.
P = mv
P = (m₁ + m₂)v
1171.77 = (120 + 75)v      <em>[solve for v]</em>
<em />v = 1171.77/195
v = 6.0091 ≈ 6.0 m/s

If asked to find direction, take inverse tan of x and y components.
tanθ = (y/x)
θ = tan⁻¹(1032/555)
[ θ = 61.73° north of east. ]

The magnitude of the velocity at which the two players move together immediately after the collision is approximately 6.0 m/s.
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