How to calculate kinetic energy of a projectile at the highest point of a projectile?

2 answers:

6 0

Kinetic energy is half the product of the mass and the square velocity and at highest point the velocity is 0 thus the kinetic energy is 0 J

DIA [1.3K]3 years ago

3 0

For a projectile the total energy is equal to the kinetic energy that is 1/2 mv and the the potential energy mgh that add. Initially the total energy is all kinetic energy at the highest point the energy is all potential.so kinetic energy at that point is 0.
hope it helps

You might be interested in

3. Suppose you take a pendulum with length L and mass m having a period T to a

natta225 [31]

(C)

Explanation:

$t = 2\pi \sqrt{ \frac{l}{g} }$

If g is only 1/6 on another planet, then

$t = 2\pi \sqrt{ \frac{l}{ \frac{g}{6} } } = 2\pi \sqrt{ \frac{6l}{g} }$

$= \sqrt{6} \: (2\pi \sqrt{ \frac{l}{g} } ) = 2.4 \times t(on \: earth)$

6 0

2 years ago

In the first-order spectrum, maxima for two different wavelengths are separated on the screen by 3.40 mm . what is the differenc

Strike441 [17]

The solution would be like this for this specific problem:

Given:

diffraction grating slits = 900 slits per centimeter

interference pattern that is observed on a screen from the grating = 2.38m

maxima for two different wavelengths = 3.40mm

slit separation .. d = 1/900cm = 1.11^-3cm = 1.111^-5 m 

Whenas n = 1, maxima (grating equation) sinθ = λ/d
Grant distance of each maxima from centre = y ..
As sinθ ≈ y/D y/D = λ/d λ = yd / D 

∆λ = (λ2 - λ1) = y2.d/D - y1.d/D
∆λ = (d/D) [y2 -y1]

∆λ = 1.111^-5m x [3.40^-3m] / 2.38m .. .. ►∆λ = 1.587^-8 m

6 0

3 years ago

How much does Nestle pay the local municipality for access to their spring water?

Lera25 [3.4K]

Around 750 to 1,500.

Hope I helped!

5 0

3 years ago

The equation that is used to solve second law problems is # F= ma.

maw [93]

F= Force
M=Mass
A= acceleration
F=N
Mass= in grams or kilo grams (mostly kg)
A= m/s

8 0

3 years ago

A balloon filled with helium occupies 20.0 l at 1.50 atm and 25.0◦

bija089 [108]

At stp (standard temperature and pressure), the temperature is T=0 C=273 K and the pressure is p=1.00 atm. So we can use the ideal gas law to find the number of moles of helium:
$pV=nRT$
where p is the pressure (1.00 atm), V the volume (20.0 L), n the number of moles, T the temperature (273 K) and $R=0.082 atm L K^{-1} mol^{-1}$ the gas constant. Using the numbers and re-arranging the formula, we can calculate n:
$n= \frac{pV}{RT}= \frac{(1.00atm)(20.0L)}{(0.082 LatmK^{-1}mol^{-1})(273 K)}=0.89 mol$

5 0

3 years ago