The answer is B. two chlorine atoms.
The chemical formula of the compound is BaCl2~
Answer:
1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻
2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)
Explanation:
Main reaction: 2Ag⁺(aq) + Mn(s) ⇄ 2Ag(s) + Mn²⁺(aq)
In the oxidation half reaction, the oxidation number increases:
Mn changes from 0, in the ground state to Mn²⁺.
The reduction half reaction occurs where the element decrease the oxidation number, because it is gaining electrons.
Silver changes from Ag⁺ to Ag.
1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻
2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)
To balance the hole reaction, we need to multiply by 2, the second half reaction:
Mn(s) ⇄ Mn²⁺(aq) + 2e⁻
(Ag⁺(aq) + 1e⁻ ⇄ Ag(s)) . 2
2Ag⁺(aq) + 2e⁻ ⇄ 2Ag(s)
Now we sum, and we can cancel the electrons:
2Ag⁺(aq) + Mn(s) + 2e⁻ ⇄ 2Ag(s) + Mn²⁺(aq) + 2e⁻
-Positively charged nucleus
-Empty spaced
-Dense core
Solutions 1 and 3 because they are strong acids and a strong base. <u>Option A.</u>
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Strong acids and strong bases are completely ionized in an aqueous solution. Weak acids and weak bases also ionize, but only partially and the reaction is reversible. So you know if an acid or base is strong or weak. A simple way to determine strength is to add the acid or base to water. A higher reactivity means a stronger acid or base.
One of the simplest tests to determine whether a solution is an acid or base is the litmus paper test. To do this, dip a special strip of paper so-called litmus paper into the solution and observe the color of the paper. Litmus paper turns red in acidic solutions and blue in basic solutions. Sodium hydroxide is the strongest base because it completely dissociates to form sodium and hydroxide ions. These hydroxide ions are further treated with hydrogen ions by an acid to completely ionize the hydrogen ions.
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