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Sonja [21]
3 years ago
10

In 2005, a Nevada silver mine exported 200 tons of silver. In 2008, as the silver supply became exhausted, it only exported 25 t

ons of silver. What is the rate of change of the mine’s silver output? A. -175/3. B. -1/50. C. 175/3. D. 75
Chemistry
2 answers:
lianna [129]3 years ago
8 0
The rate of change in the amount of silver supplied is equal to the ratio of the difference in the amount supplied to the number of years elapsed from 2005 to 2008. That is,
               rate of change = (25 - 200) / (2008 - 2005) = -173/3
The answer is letter A. 
Anit [1.1K]3 years ago
5 0

Answer:

The correct answer is option A.

Explanation:

Amount of silver exported in 2005 = 200 tons

Amount of silver exported in 2008 = 25 tons

Rate of change of silver output:

\frac{\text{Silver exported in 2008}-\text{Silver exported in 2005-}}{\text{time elapsed}}=\frac{25-200}{2008-2005}=\frac{-175}{3}

Hence, the correct answer is option A.

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select which of the following correctly represents the BALANCED chemical reaction for the production of HCL gas from its element
bagirrra123 [75]

Answer:

Choices 2 and 4

Explanation:

HCL is formed witthe the elements Hydrogen and Chlorine. Whatever is on the left side of the equation must match up with the right side of the equation.

2. H + Cl --> HCl (we have one hydrogen and one chlorine)

4. 2HCl --> H2 + Cl2 (since the two is distributed to both the H and the Cl, H has 2 and Cl has two on the left side AND on the right side of the equation)

3 0
2 years ago
The irreversible elementary gas-phase reaction is carried out isothermally at 305 K in a packed-bed reactor with 100 kg of catal
tamaranim1 [39]

Answer:

0.856.

Explanation:

Lets represent the irreversible elementary gas phase equation of reaction as

A + B -----------------------------------> C + D

We have that the percentage of conversion is 80%.

The pressure, p from the ratio of exit pressure and entering pressure is p = 2/20 = 1/10 = 0.1.

Therefore, n = 1 - p^2/ weight of the catalyst = 1 - 0.1^2/ 100 = 9.9 × 10^-3 kg cat^-.

Now, let's make use of the equation below;

J/ 1 - J = kb^2/ u [ w - nw^2/2] ----------(1).

0.8 / 1- 0.8 = k ( 0.4)^2/ 10 [ 100 - (9.9× 10^-3 × 100^2/ 2] .

k = 4.95 dm^6/ kg.cat .mol.min

The turbulent flow= 1/2 × 9.9 × 10^-3 = 4.95 × 10^-3 kg cat^-.

Thus, making use of the equation (1) again, we have that;

{4.95 × 10^-3 × 0.4}/ 10 × [ 100 - (4.95 × 10^-3 × 100^2)] / 2 = 5.964.

Therefore, a/1 - a = 5.964.

5.964( 1 - a) = a.

5.964 - 5.964a = a.

5.964 = a + 5.964a.

5.964 = 6.964a.

a = 5.964/ 6.964 = 0.856.

5 0
2 years ago
HClO4 acid solution has a concentration of 5 Molarity. Calculate the concentration of this solution in
Nutka1998 [239]

Answer:

1. Percentage by weight = 0.5023 = 50.23 %

2. molar fraction =0.153

Explanation:

We know that

Molar mass of HClO4 = 100.46 g/mol

So the mass of 5 Moles= 5 x 100.46

       Mass (m)= 5 x 100.46 = 502.3 g

Lets assume that aqueous solution of HClO4  and the density of solution is equal to density of water.

Given that concentration HClO4 is 5 M it means that it have 5 moles of HClO4 in 1000 ml.

We know that

Mass = density x volume

Mass of 1000 ml  solution = 1 x 1000 =1000     ( density = 1 gm/ml)

            m'=1000 g

1.

Percentage by weight = 502.3 /1000

Percentage by weight = 0.5023 = 50.23 %

2.

We know that

molar mass of water = 18 g/mol

mass of water in 1000 ml = 1000 - 502.3 g=497.9 g

So moles of water = 497.7 /18 mole

moles of water = 27.65 moles

So molar fraction = 5/(5+27.65)

molar fraction =0.153

6 0
3 years ago
If element A has an ionic charge of +2 and element B has an ionic charge of -3, what will be the formula for the compound create
Softa [21]
A3B2 because the oxidation numbers are the same as ionic charge just switch symbol and number. Then use the cross cross method and you get A3B2.
8 0
3 years ago
Which feature do you usually see when tectonics plates move apart?
exis [7]
A. new ocean ridges and seafloor 
5 0
3 years ago
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