Question

An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0 L tank?

Answer 1

Answer:

1.2 atm

Explanation:

Given data

• Volume of the gas in the tank (V₁): 200.0 L

• Pressure of ethylene gas in the tank (P₁): ?

• Volume of the gas in the torch (V₂): 300 L

• Pressure of the gas in the torch (P₂): 0.8 atm

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

$P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm$