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coldgirl [10]
3 years ago
7

Which of the following are also major levels of classification?

Chemistry
1 answer:
const2013 [10]3 years ago
7 0
The answer is A and B. <span> kingdom, phylum, class, order, family, genus and species.</span>
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26. A Grignard's reagent may be made by
Marat540 [252]
Its pretty easy, correct answer is D
8 0
3 years ago
Can someone please help me with my science research I kind of need help in a few things that I listed, I’m currently working on
dalvyx [7]

Answer:

For your first question, Curium does not occur naturally on Earth, meaning that it is not produced naturally on Earth. However, it can be formed in nuclear reactors.

For your second question, Curium has been used to provide power to electrical equipment used on space missions, but doesn't seem to be that important overall.

Explanation:

Hope this helped!

7 0
3 years ago
A rigid container of O has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273 K?
tia_tia [17]

Answer:

P₂ = 130.18 kPa

Explanation:

In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:

P₁/T₁ = P₂/T₂   (1)

From here, we can solve for the Pressure at 273 K:

P₂ = P₁ * T₂ / T₁   (2)

Now, all we need to do is replace the given data and solve for P₂:

P₂ = 340 * 273 / 713

<h2>P₂ = 130.18 kPa</h2>

Hope this helps

4 0
3 years ago
sulfate = SO4 -2 phosphate = PO4 -3 hydroxide = OH- sodium hydroxide aNa(OH)2 bNa(OH)3 cNa2OH 4NaOH
blsea [12.9K]
4. NaOH
____________________________________
6 0
3 years ago
13. How many moles of sodium hydroxide are needed to neutralize 50grams of sulfuric acid?
Phoenix [80]

Answer:

1.02mole

Explanation:

The reaction equation is given as:

     2NaOH  +  H₂SO₄ →  Na₂SO₄  + 2H₂O

Given:

Mass of H₂SO₄  = 50g

Unknown:

Number of moles of NaOH = ?

Solution:

To solve this problem, we first find the number of moles of the acid given;

  Number of moles  = \frac{mass}{molar mass}

Molar mass of H₂SO₄ = 2(1) + 32 + 4(16)  = 98g/mol

Now;

   Number of moles = \frac{50}{98}   = 0.51mole

From the balanced reaction equation:

       1 mole of H₂SO₄ will be neutralized by 2 mole of NaOH

     0.51 mole of H₂SO₄ will be neutralized by 2 x 0.51  = 1.02mole of NaOH

6 0
3 years ago
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