Answer:
Explanation:
In this problem we only have information of the equilibrium, so we need to find a expression of the free energy in function of the constant of equilireium (Keq):
Being Keq:
![K_{eq}=\frac{[fructose][Pi]}{[Fructose-1-P]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5Bfructose%5D%5BPi%5D%7D%7B%5BFructose-1-P%5D%7D)
Initial conditions:
![[Fructose-1-P]=0.2M](https://tex.z-dn.net/?f=%5BFructose-1-P%5D%3D0.2M)
![[Fructose]=0M](https://tex.z-dn.net/?f=%5BFructose%5D%3D0M)
![[Pi]=0M](https://tex.z-dn.net/?f=%5BPi%5D%3D0M)
Equilibrium conditions:
![[Fructose-1-P]=6.52*10^{-5}M](https://tex.z-dn.net/?f=%5BFructose-1-P%5D%3D6.52%2A10%5E%7B-5%7DM)
![[Fructose]=0.2M-6.52*10^{-5}M](https://tex.z-dn.net/?f=%5BFructose%5D%3D0.2M-6.52%2A10%5E%7B-5%7DM)
![[Pi]=0.2M-6.52*10^{-5}M](https://tex.z-dn.net/?f=%5BPi%5D%3D0.2M-6.52%2A10%5E%7B-5%7DM)
Free-energy for T=298K (standard):
Answer:
3
Explanation:
102 are significant figures
Explanation: a homogeneous mixture forms when two or more substances are combined to make something uniform. In this type of mixture, the components must be evenly distributed troughout. Only one state of matter can be present and you can see individual ingredients.
Answer:
The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Argon, or 39.948 grams. Note that rounding errors may occur, so always check the results. Use this page to learn how to convert between moles Argon and gram.
Explanation:
please mark me brainliest
Answer:
Their parents share 1 gene each to the offspring's DNA
