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madreJ [45]
3 years ago
15

If 28 ml of 5.4 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?

Chemistry
1 answer:
Ainat [17]3 years ago
7 0

A reaction between acid and base to form water and salt is known as neutralization reaction. It is a double replacement reaction.  

The reaction between H_2SO_4 and NaHCO_3 will be:

H_2SO_4 + NaHCO_3 \rightarrow Na_2SO_4 + CO_2 + H_2O

The balanced reaction is:

H_2SO_4 + 2NaHCO_3 \rightarrow Na_2SO_4 + 2CO_2 + 2H_2O

Volume of H_2SO_4 = 28 mL (given)

Since, 1 L = 1000 mL

So, 28 mL = 0.028 L

Molarity of H_2SO_4 = 5.4 M (given)

Molarity = \frac{number of moles of solute}{Volume of solution in Liters}   -(1)

Substituting the values in equation (1):

5.4 mol/L = \frac{number of moles of H_2SO_4}{0.028 L}

number of moles of H_2SO_4 = 5.4 mol/L\times0.028 L

number of moles of H_2SO_4 = 0.1512 mol

From the balanced reaction between H_2SO_4 and NaHCO_3, 2 moles of NaHCO_3 reacts with 1 mole of H_2SO_4.

Molar mass of NaHCO_3 = 84.007 g/mol

Mass of NaHCO_3 needed:

0.1512 mol H_2SO_4 \times \frac{2 mole NaHCO_3}{1 mole H_2SO_4}\times \frac{84.007 g}{1 mole NaHCO_3} = 25.404 g

Hence, the required amount of NaHCO_3 is 25.404 g.


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7 0
3 years ago
Consider the following equilibrium:
Ainat [17]

<u>Answer: </u>The equation which is wrong is K_p=K_c(RT)^{-5}

<u>Explanation:</u>

For the given reaction:

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

The expression for K_c\text{ and }K_p is given by:

K_c=\frac{1}{[O_2]^3}

K_p=\frac{1}{[O_2]^3}

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between K_p\text{ and }K_c is given by the expression:

K_p=K_c\times (RT)^{\Delta n_g}

where,

\Delta n_g= number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

\Delta n_g = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for K_p is:

K_p=K_c\times (RT)^{-3}

Therefore, the equation which is wrong is K_p=K_c(RT)^{-5}

7 0
3 years ago
_____ bonds are formed when the electronegativity difference is 0.4 &gt; 2.0. Give two examples:
34kurt

<u>Ionic Bond</u> is formed when the electronegativity difference is 0.4 > 2.0. Electronegativity is a term that can be defined as a tendency of an atom to attract electron towards its own self.

Explanation:

Electronegativity is a term that can be defined as a tendency of an atom to attract electron towards its own self.

An  electronegativity of an atom is affected by

  • The atomic number of the atom
  • Secondly by the distance at which the valence electron are residing from the nucleus

1. In case the  electronegativity difference (which is denoted by  ΔEN) is less than 0.5  then the bond formed is known as N<u>onpolar covalent. </u>

2. In case  the ΔEN is in between 0.5 and 1.6, the bond formed is referred to as the<u> Polar covalent </u>

3. In case  the ΔEN is more /greater  than 2.0, then the bond formed is referred to as<u> Ionic Bond</u>

<u>2 Examples of Ionic bonds</u>

  • The formation of sodium fluoride, NaF, from a sodium atom and a fluorine atom is an example of Ionic bond formation.
  • Another example is the formation of NaCl from  sodium (Na),which is  a metal, and chloride (Cl), which is a  nonmetal

6 0
3 years ago
What is the ph of a solution that has a poh of 11.24
galina1969 [7]
Always remember that pH + pOH = 14 
Here, you have a pOH of 11.24, so  you replace it in the equation, and u get:
pH + 11.24 = 14

Then, You move 11.24 to the other part. and moving from a part to another change the sign of the equation. And you get:
pH = 14 - 11.24 = 2.76

So, the pH of a solution that has a pOH of 11.24 is pH = 2.76

Hope this Helps :)
7 0
3 years ago
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