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Anettt [7]
4 years ago
5

PLZZZZ NEEDDD HELPPPO‼️‼️​

Chemistry
1 answer:
svlad2 [7]4 years ago
7 0

Answer:

1.) When Mendeleev arranged the elements in order of increasing atomic mass, the properties where repeated. Because the properties repeated themselves regularly, or periodically

2.) i can't really answer this one because it's not a direct question but if you get your periodic table and look at the list that it gave you look at which elements are in the same row and you you will get the correct answer that way

3.)  and this question is referring back to question two so just pick one of the idem ( this means chose a name of an element) alkali elements and say because you mixed up alkaline and alkali and you figured it out by remembering what group and what row it was in

4.) name an element that can't be put into one group and chose this from the alkali group

5.) the number of valence electrons stays the same as you go up or down a group, but they increase as you go from left to right across the periodic table.

6.) sorry i don't really know how to explain this one

Explanation:

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Does anyone know o I'm correct? If not what's the answer?
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I believe it means idea because a Web is out line to a a more structured idea
6 0
3 years ago
A box contains 104 gas molecules, 2500 of nitrogen and 7500 of argon in thermal equilibrium. The molecular weight of N2 is 28g/m
LekaFEV [45]

Answer : The temperature of this gas will be, 206.9 K

Explanation :

The expression for the kinetic energy per molecule of monoatomic gas (argon) is:

K.E_{argon}=n_{argon}\times \frac{3}{2}\times K_BT      ...........(1)

The expression for the kinetic energy per molecule of diatomic gas (nitrogen gas) is:

K.E_{nitrogen}=n_{nitrogen}\times \frac{5}{2}\times K_BT      .............(2)

The total kinetic energy of the molecule will be,

K.E_{Total}=K.E_{argon}+K.E_{nitrogen}

Now put all the expression in this, we get:

K.E_{Total}=(7500)\times \frac{3}{2}\times K_BT+(2500)\times \frac{5}{2}\times K_BT

T=\frac{K.E}{17500\times K_B}

Now put all the given values in this expression, we get:

T=\frac{5\times 10^{-17}J}{17500\times (1.381\times 10^{-23}J/K)}

T=206.9K

Therefore, the temperature of this gas will be, 206.9 K

8 0
4 years ago
What mass of each solute is present in 294 g of a solution that contains 4.86% by mass NaCl and 7.54% by mass Na2CO3
Angelina_Jolie [31]
In order to compute the mass of each solute in the sample, we simply multiply the percentage mass of each solute with the total mass of the solution. This is ad such:
Mass (NaCl) = 0.0486 x 294
Mass (NaCl) = 14.29 grams

Mass(Na₂CO₃) = 0.0754 x 294
Mass(Na₂CO₃) = 22.17 grams
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