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3 years ago

PLZZZZ NEEDDD HELPPPO‼️‼️

Chemistry

1 answer:

svlad2 [7]3 years ago

7 0

Answer:

1.) When Mendeleev arranged the elements in order of increasing atomic mass, the properties where repeated. Because the properties repeated themselves regularly, or periodically

2.) i can't really answer this one because it's not a direct question but if you get your periodic table and look at the list that it gave you look at which elements are in the same row and you you will get the correct answer that way

3.) and this question is referring back to question two so just pick one of the idem ( this means chose a name of an element) alkali elements and say because you mixed up alkaline and alkali and you figured it out by remembering what group and what row it was in

4.) name an element that can't be put into one group and chose this from the alkali group

5.) the number of valence electrons stays the same as you go up or down a group, but they increase as you go from left to right across the periodic table.

6.) sorry i don't really know how to explain this one

Explanation:

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The noble gases are located in which column of the periodic table?A. 1B. 6C. 9D. 18

Vika [28.1K]

D IS THE ANSWER TO YOUR QUESTION

6 0

3 years ago

Oceń prawdziwość podanych informacji w układzie okresowym pierwiastki chemiczne są złożone według NIK to jących się liczbą atomo

cluponka [151]

Wow. What language is this?

3 0

3 years ago

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

3 0

3 years ago

Consider the equilibrium reaction and its equilibrium constant expression. Br 2 ( g ) + 2 NO ( g ) − ⇀ ↽ − 2 NOBr ( g ) K = [ NO

zavuch27 [327]

Answer:

$K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}$

Explanation:

Hello,

In this case, for the equilibrium condition, the equilibrium constant is defined via the law of mass action, which states that the division between the concentrations of the products over the concentration of the reactants at equilibrium equals the equilibrium constant, for the given reaction:

$2 Br_2 ( g ) + 4 NO ( g ) \rightleftharpoons 4NOBr ( g )$

The suitable equilibrium constant turns out:

$K_2=\frac{[NOBr]^4_{eq}}{[NO]^4_{eq}[Br]^2_{eq}}$

Or in terms of the initial equilibrium constant:

$K_2=K_1^2$

Since the second reaction is a doubled version of the first one.

Best regards.

5 0

3 years ago

From a scientific viewpoint, why do many desert dwellers elect to wear white or light-colored garments

alexandr1967 [171]

Darker colors absorb sunlight more, so it will become hotter. Lighter colored clothes will better reflect sun so they will be less hot.

Hope that helped

7 0

3 years ago

PLZZZZ NEEDDD HELPPPO‼️‼️​

PLZZZZ NEEDDD HELPPPO‼️‼️