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Anettt [7]
3 years ago
5

PLZZZZ NEEDDD HELPPPO‼️‼️​

Chemistry
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

1.) When Mendeleev arranged the elements in order of increasing atomic mass, the properties where repeated. Because the properties repeated themselves regularly, or periodically

2.) i can't really answer this one because it's not a direct question but if you get your periodic table and look at the list that it gave you look at which elements are in the same row and you you will get the correct answer that way

3.)  and this question is referring back to question two so just pick one of the idem ( this means chose a name of an element) alkali elements and say because you mixed up alkaline and alkali and you figured it out by remembering what group and what row it was in

4.) name an element that can't be put into one group and chose this from the alkali group

5.) the number of valence electrons stays the same as you go up or down a group, but they increase as you go from left to right across the periodic table.

6.) sorry i don't really know how to explain this one

Explanation:

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Inessa05 [86]

Answer:

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Explanation:

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5 0
3 years ago
When two 1s hydrogen atoms combine to form h2, the bond formed is:?
Tanya [424]
H2 is a covalent bond. Each hydrogen atom shares its single electron to the other, so each hydrogen has two valence electrons (full outer shell).
5 0
3 years ago
If you mix water and vinegar together, will it form a solid?
natka813 [3]
No, but. It will seperate into two different layers based on density
4 0
3 years ago
Balance the following equation in acidic conditions. Phases are optional. Cu NO3,
Gwar [14]
If your equation is <span>Cu+NO^- 3-->Cu^2+NO, then the answer is 
</span><span>2 Cu + 1 NO3{-}  → 1 Cu^{2+} + 3 NO 
</span>
To check if it is balance, this is the solution:
2- Cu- 2
3- N -3
3- O -3 

5 0
3 years ago
How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution?
Ksenya-84 [330]

Answer:

a. Approximately 1.3\; \rm mL.

b. Approximately 7.2\; \rm mL.

Explanation:

The unit of concentration "\rm M" is equivalent to "\rm mol \cdot L^{-1}", which means "moles per liter."

However, the volume of both solutions were given in mililiters \rm mL. Convert these volumes to liters:

\displaystyle 45\; \rm mL = 45\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.045\; \rm L.

\displaystyle 330\; \rm mL = 330\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.330\; \rm L.

In a solution of volume V where the concentration of a solute is c, there would be c \cdot V (moles of) formula units of this solute.

Calculate the number of moles of \rm NaCl formula units in each of the two solutions:

Solution in a.:

n = c \cdot V = 0.045\; \rm L \times 0.10\; \rm mol \cdot L^{-1} = 0.0045\; \rm mol.

Solution in b.:

n = c \cdot V = 0.330\; \rm L \times 0.074\; \rm mol \cdot L^{-1} = 0.02442\; \rm mol.

What volume of that 3.4\; \rm M (same as 3.4 \; \rm mol \cdot L^{-1}) \rm NaCl solution would contain that many

For the solution in a.:

\displaystyle V = \frac{n}{c} = \frac{0.0045\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0013\; \rm L.

Convert the unit of that volume to milliliters:

\displaystyle 0.0013\; \rm L = 0.0013\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 1.3\; \rm mL.

Similarly, for the solution in b.:

\displaystyle V = \frac{n}{c} = \frac{0.02442\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0072\; \rm L.

Convert the unit of that volume to milliliters:

\displaystyle 0.0072\; \rm L = 0.0072\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 7.2\; \rm mL.

8 0
3 years ago
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