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My name is Ann [436]
3 years ago
8

Which example involves a phase change in which heat energy is released by the substance

Chemistry
1 answer:
a_sh-v [17]3 years ago
7 0

What are the examples?


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PLEAZE HELP!!!
Alla [95]

Answer:

V= 12mL

Explanation:

you had the right idea with your Significant figures however, when we divide we see that it requires 2 significant figures as our least amount. this is because when looking at our division, 62 has 2 sig. fig. while 5.35 has a total 3. when looking at your answer we see that you had a total of 3 sig. figures. so in actuakity you had to round up to 12 and not to the tenths because the decimal makes .6 count as your third sig fig.

7 0
3 years ago
Which is NOT a way nitrogen can be fixed or made more useful?
stich3 [128]
This doesn’t have a multiple choice part to answer.
7 0
3 years ago
Which descriptions apply to emitted radiation? check all that apply?
Murrr4er [49]
<span>measurement in Ci/Bq

the amount of radioactive materials released into the environment.

number of disintegrations of radioactive atoms in a radioactive material over a period of time</span>
7 0
3 years ago
NaOH(aq) is transferred into a test tube. CaCl2(aq) is added to the tube. What is the formula for the precipitate (if any) that
Ilya [14]

Answer:

2NaOH (aq) + CaCl2 (aq) -> 2NaCl(aq) + Ca(OH)2(s)

Formula of precipitate: Ca(OH)2 <em>(s)</em>

Explanation:

First, we do the double replacement reaction to determine our chemical equation between the reactants and products. Once we have our products, with a solubility chart (I added one below) we can determine which of the products is soluble or insoluble.

In this case NaCl is soluble or aqueous (meaning it can dissolve in water) and Ca(OH)2 is insoluble (meaning that when the reactions takes place, these two will form a solid/precipitate)

6 0
2 years ago
If a car is traveling 100 km/h and comes to a stop in 3 minutes,what is acceleration of a passenger who is using vehicle restrai
Rama09 [41]

We are given –

  • Final velocity of car is, v= 0
  • Initial velocity of car is, u= 100 km/hr
  • Time taken, t is = 3 minutes or 180 sec

Here–

\qquad\pink{\bf \longrightarrow  Initial\:  velocity =  100 \:km/hr}

\qquad\sf \longrightarrow  Initial\:  velocity = \dfrac{ 100 \times 1000}{3600} \:m/s

\qquad\pink{ \bf \longrightarrow  Initial\:  velocity = 27.78\: m/s}

Now –

\qquad____________________________

\qquad\purple{\bf \longrightarrow  Acceleration  = \dfrac{Final\: Velocity -Initial  \:Velocity }{Time}}

\qquad\purple{\bf \longrightarrow  Acceleration  = \dfrac{v -u}{t}}

\qquad\sf \longrightarrow  Acceleration = \dfrac{(0- 27.78)}{1800}

\qquad\sf \longrightarrow  Acceleration =\cancel{ \dfrac{- 27.78}{1800}}

\qquad\purple{\bf \longrightarrow  Acceleration = -0.15 \: m/s^2}

\qquad_______________________________

6 0
2 years ago
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