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My name is Ann [436]
3 years ago
8

Which example involves a phase change in which heat energy is released by the substance

Chemistry
1 answer:
a_sh-v [17]3 years ago
7 0

What are the examples?


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A student touches a freshly baked cake that was taken out of the oven. Which best explains why the cake feels hot? Options: Mole
chubhunter [2.5K]

Answer:

Molecules in the cake are moving faster than molecules in the skin.

Explanation:

When a cake is baked, the energy is absorbed. This is known as an endothermic reaction. When things are hot, it means that the molecules are in motion. When the cake is taken out from the oven, the molecules are continuously moving and absorbing energy. When the student touches the cake, the heat is flown into the student's body. This happens because of the difference in the temperature between the two.

4 0
3 years ago
What evidence do you have that the slope of the natural logarithm plot will be the same for all ions of the same charge, and not
dimulka [17.4K]

Answer:

See explaination

Explanation:

1) As Evidence we just need to observe the nernst equation,

E = E0 + 2.303 RT / nF log QR

E = cell potential

E0 = Standard cell potential

R = Universal gas constant 8.314 J/K Mol

n = Valency of ion

F = faradays constant 96485 C/ mol

T = temperature in Kelvin

QR = Reaction quocient

If we plot a graph between E and Concentration of ion , We get a straight line according to the equation y = mx + C. that is the nernst equation is in the form of equation of a straight line.

E = E0 + 2.303 RT / nF log QR

Here the slope will be 2.303 RT / nF.

That is if we are measuring the electrode potential at a constant temperature , the only factor which affects the slope will be the the charge of ions 'n'. If n is same for all the ions used the slope of natural logaritham plot wil be same.

if n = 1, at room temperature ( 273 + 25 = 298 K)

2.303 * 8.134 * 298 / 1 * 96486 = 0.0591

Thus it can be concluded that the slope of natural logarithm plot will be same for all ions of the same charge.

2) The Zn metal undergo Oxidation,

Zn(s) \rightarrow Zn2+ (Aq) + 2 e-

Copper undergo Reduction

Cu2+ (Aq)+ 2 e-\rightarrow Cu (s)

The standard electrode potential for the reaction is 1.10 V

Here what happens to Zinc is dissolution into the solution , that is oxidation and what happens at copper is deposition. As Zinc ions goes into the solution , accumulation of Zinc ions around the zinc electrode takes place. ant the electron realeased into the solution reaches to the copper solution through the wire connected between them. copper ions accepts the electron and turns into copper atom (Reduction) and gets deposited at the copper electrode. This electron flow is the current generated.

As copper ions gets reduced and deposits on the copper electrode the copper ions in the solution decreases. Ultimately a situation comes where the zn ions dissolution stops because the zn ions surrownding the anode repells the zn electrode and oxidation stops. At the cathode the absence of cu2+ at cathode electrode interface stops the deposition of at copper electrode also. In short the oxidation and reduction reactions stops . This means that the cell battery power is all used up. A battrery consist of galvanic cell. batteries stores energy in chemical form and deliver it as electrical energy through electrochemical reaction as explained above. when half reactions stops in the battery no current flow takes place and battery stops.

6 0
4 years ago
What is the balanced chemical reaction when Aluminium reacts with NaOH to produce NaAlO2 and H2 gas?​
8090 [49]

Answer:

2NaOH + 2Al +2H2O = 2NaAlO2 +3H

Explanation:

Aluminum is an amphoteric element it reacts with both bases and acids to form a salt and hydrogen gas.The reaction is highly exothermic.

5 0
3 years ago
__PbSO4 → __ PbSO3 +__O2<br><br> Balance the equation and indicate the type of reaction
shutvik [7]

<h2>Answer :2PbSO4 → 2PbSO3 + O2 </h2>

5 0
3 years ago
If you have 2 Moles of C3H6 and 10 Moles of O2, which reactant is limiting the following reaction: 2C3H6 + 9O2 → 6CO2 + 6H2O?
Hatshy [7]

Answer:

The limiting reactant is propene, C_3H_6.

Explanation:

2C_3H_6 + 9O_2 \rightarrow 6CO_2 + 6H_2O

Moles of nitrogen propene  = 2 mol

Moles of oxygen  = 10 mol

According to reaction, 2 moles of propene reacts with 9 moles of oxygen gas, then 2 moles of propene will react with:

=\frac{9}{2}\times 2mol=9\text{mol of oxygen gas}

According to the question, we have 10 moles of oxygen gas, which is more than 9 moles of oxygen gas. This indicates that propene is present in a limiting amount hence, it is a limiting reactant.

The limiting reactant is propene, hence the correct answer is the C_3H_6.

5 0
3 years ago
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