Answer:
Option 4 is correct (72 seconds)
Explanation:
Option 4 is correct (72 seconds)
The formula we are going to use is:
![ln\frac{A}{A_o}=-kt](https://tex.z-dn.net/?f=ln%5Cfrac%7BA%7D%7BA_o%7D%3D-kt)
Where:
A is the final concentration
A_o is the initial concentration
k is the constant
t is the time
Half-Life=0.693/k
Half-life in our case=24 seconds
k=0.693/24
k=0.028875 s^-1
Since the concentration is decreased by 87.5 % which means only 12.5%(100-87.5%) is left.
The ratio
will become 0.125
![ln 0.125=-0.028875*t\\t=72.015\ seconds](https://tex.z-dn.net/?f=ln%200.125%3D-0.028875%2At%5C%5Ct%3D72.015%5C%20seconds)
t≅ 72 seconds
You are travelling around a curve at constant speed.
<span>(Direction changes, therefore velocity changes, so that is acceleration) -A</span>
Answer:
We can just use the formula for the volume of sphere which is 4/3 PI R cubed R is the radius. So if you have a balloon that's a sphere.
Explanation:
The equations are as follow,
A) HCN (aq) + H₂O (l) ↔ H₂CN⁺ (aq) + OH⁻<span> (aq)
B) </span>H₂O (l) ↔ H⁺ (aq) + OH⁻ (aq)
C) HCN (aq) ↔ H⁺ (aq) + CN⁻ <span>(aq)
D) </span>HCN (aq) + H₂O (l) ↔ CN⁻ (aq) + H₃O⁺<span> (aq)
E) </span>HCN (aq) ↔ H⁻ (aq) + CN⁺<span> (aq)
Answer:
<u>Option-D </u>is the correct answer.
Explanation:
When hydrogen cyanide is added in water it partially ionizes as follow,
</span> HCN (aq) + H₂O (l) ↔ CN⁻ (aq) + H₃O⁺ (aq)
Being weak acid it fails to completely dissociate into H⁺ and CN⁻ ions. In this reaction water is acting as a Bronsted Lowery Base and picks proton from from HCN and converts into conjugate acid (i.e. H₃O⁺), while, HCN converts into conjugate Base (i.e. CN⁻).