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SSSSS [86.1K]
3 years ago
12

3. Determine which ordered pair is not a solution of y = –5x – 4.

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

A

Step-by-step explanation:

Let's try choice A.

y = -5x-4

(10, -52)

-52 = -5(10)-4

-52 = -50-4

-52= -54

-52 is not equal to -54, so A is the answer.

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27x^2−9y^2=81

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W varies jointly as x and p . If w=78 when x=2 and p=10, find x when w=858 and p=5.5
Lemur [1.5K]
W=kxp
where
k is the constant of proportionality given by:
k=w/xp
<span> If w=78 when x=2 and p=10 then
</span>k=78/(2*10)
k=3.9
thus the formula is:
w=3.9xp


b] <span>find x when w=858 and p=5.5
plugging the values in the formula we get:
858=3.9</span>×5.5×x
hence 
x=858/(3.9×5.5)
x=358/21.45
x=16.69
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3 years ago
Carpet a room 12ft by 8ft. How many yards of sq carpet
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You need 96 Square yards of carpet
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6 0
4 years ago
Suppose you have a bag containing 15 red beads, 12 white beads and 8 black beads. You are going to draw one bead out of the bag.
iren [92.7K]

Answer:

probability that you draw a black bead or a white bead that is P(E1 U E2)

= 20/35 = 0.571

Step-by-step explanation:

Given a bag containing 15 red beads, 12 white beads and 8 black beads

n(S) = 15 + 12 +8 = 35

Let 'E1 be the event of selecting black beads and E2 be the event of selecting white beads

n(E1) = 8 and n(E2) = 12

Probability of draw a black bead P( E1 ) = \frac{n(E_{1} )}{n(S)}

                                                      P(E_{1}) = \frac{8}{35}

Probability of draw a white bead P( E2 ) = \frac{n(E_{2} )}{n(S)}

                                                    P(E_{2}) = \frac{12}{35}

probability that you draw a black bead or a white bead that is P(E1 U E2)

and E1 n E2 = ∅ (disjoint events)

<u>Axiom of union </u>

<u></u>P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - P(E_{1}nE_{2})\\<u></u>

E1 n E2 = ∅ ⇒ P(E1 n E2) = p(∅) = 0

P(E_{1}UE_{2} ) = P(E_{1})+P(E_{2}) - 0

P(E_{1}UE_{2} ) = \frac{8}{35} +\frac{12}{35}

P(E_{1}UE_{2} ) = \frac{20}{35}

P(E_{1}UE_{2} ) = 0.571

8 0
4 years ago
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