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joja [24]
3 years ago
5

Michael is taking a survey of students at his high school to find out how many hours they work per week. He surveys all of the s

tudents in his Freshman English class. Is this a good sampling method? A 15 foot flagpole casts an 11 foot shadow. At the exact same time a 28 foot tree casts a shadow. Which proportion would correctly find the length of the tree's shadow?
Mathematics
1 answer:
iren2701 [21]3 years ago
7 0
The Proportion for the 15/11=28/x
let x be the shadow that is cast by the tree.
so x=(11*28)/15
x= 20.533
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What is 29 divided by 11​
dezoksy [38]

Answer:

2.63

Step-by-step explanation:

29/11=2.63

4 0
3 years ago
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a student's cost for last semester at her community college was $2400. she Spent $360 of that on books. what percent of last sem
poizon [28]
360 / 2400 = 0.15 = 15% <==
3 0
3 years ago
40 points for this question! Algebra 2. With all explanation, please!
const2013 [10]
You will need three roots for this, so we have
 Let x = -30, -10 and +20
So the factors will be  (x+30)(x+10)(x-20)
The divide it to 100, this will help bring the peak up and down
So the polynomial function R(x) will become
1/100 *  (x+30)(x+10)(x-20)
R(x) = 1/100 * (x+30)(x+10)(x-20)
 
Finding the X-intercept:
Let R(x) = 0 and solve for x.
1/100 * (x+30)(x+10)(x-20) = 0
x = -30, -10, 20 are the x-intercepts.

3 0
2 years ago
a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

4 0
2 years ago
Please help:)<br> will give brainliest
vlada-n [284]
I’m pretty sure the average rate is 2 sorry if I’m wrong have a gre day
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2 years ago
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