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Archy [21]
3 years ago
15

A man invested a portion of $3,600 at 8% annual interest and the balance at 7%. If he receives $264 interest during the first ye

ar how much did he invest at each rate?
Mathematics
1 answer:
natta225 [31]3 years ago
6 0
0.08x+0.07 (3600-x)=264
Solve for x
0.08x+252-0.07x=264
0.08x-0.07x=264-252
0.01x=12
X=12÷0.01
X=1200 invested at 8%

3600-1200=2400 invested at 7%
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2 years ago
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sleet_krkn [62]

Answer:

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Step-by-step explanation:

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4(x-2)+2x=10

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And So the Final Answer is:

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8 0
3 years ago
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