Answer:
Explanation:
We shall represent each displacement by vectors . i will represent east , -i west , j north and - j south .
Rhino walks 1.5 km west on day 1.
D₁ = - 1.5 i
The rhino then moves 0.7 km on a straight line in a direction of 15o east of north toward ground camera B
D₂ = .7 sin15 i + .7cos15 j
On the second day, the rhino moves 2.5 km directly south
D₃ = - 2.5 j
D = D₁ + D₂ + D₃
= - 1.5 i + .7 sin15 i + .7cos15 j - 2.5 j
= - 1.5 i + .181 i + .676 j - 2.5 j
= - 1.32 i - 1.824 j
magnitude of total displacement
= √ (1.32² +1.824²
= 2.25 km
For direction we shall calculate slope with x axis
Tanθ = - 1.824 / - 1.32
= 54°
So rhino will be towards 54° south of west as both x and y coordinates are negative.
The "blue" object would look the same. Say that this blue object is a square. That "square" is every color but blue. The only reason that you see it as "blue" is because what we call "blue", it the only color of light that bounces back at our eyes. Under all colors of light, especially simultaneously. This square or any shape for that matter would absorb the other colors of light, but the blue will be rejected. Therefore, we can only see what bounces back at our eyes, which is the color blue in this case.
Hope this helps, WyattMarine501
Answer:

Explanation:
As we know that the tension in two strings are


now we have

so we can say


also we have


now divide two equations



round the corners of the magnet that where it is stronger
hope this helps :)