Dynamo converts the

Physics

2 answers:

Sav [38]4 years ago

6 0

Answer:

$\gamma \: dynamo \: converts \: the \: mechanical \: energy \: into \: electrical \: energy \: .$

Explanation:

Hope it helps you :)))

Andre45 [30]4 years ago

5 0

Answer:

Explanation:

You might be interested in

Consider a planet with a surface temperature of 50 K an escape speed of 30 km/s. What type of planet must this be?

Ilya [14]

Answer:

option A. Jovian

Explanation:

If we consider the temperature of the planet which is 50 K, shows that the planet is quite distant from the central point of the solar system which itself shows one of the characteristics of Jovian planets.

If escape velocities of the planets are to be considered than for terrestrial planets like that of our Earth, the escape velocity must be similar to that of the Earth which is 11.2 Km/s, quite a smaller value as the gravitational pull of Earth is stronger than that of the Jovian planets with much higher values of escape velocities as the mentioned one here is 30 km/s which is again indicative of the planet being a Jovian planet.

4 0

3 years ago

An object in equilibrium has a net force of

Butoxors [25]

Answer:

An object in equilibrium has a net force of zero

Static equilibrium describes an object at rest having equal and balanced forces acting upon it.

Dynamic equilibrium describes an object in motion having equal and balanced forces acting upon it.

Explanation:

An object is said to be in equilibrium when a net force of zero is acting on it. When this condition occurs, the object will have zero acceleration, according to Newton's second law:

$F=ma$

where F is the net force, m the mass of the object, a the acceleration. Since F=0, then a=0. As a result, we have two possible situations:

- If the object was at rest, then it will keep its state of rest. In this case, we talk about static equilibrium.

- If the object was moving, it will keep moving with constant velocity. In this case, we talk about dynamic equilibrium.

8 0

3 years ago

A lacrosse ball leaves the sick horizontally at 12.0m/s. the catcher is 14.0 away. How much does the ball fall vertically travel

boyakko [2]

Answer:

1.65 m

Explanation:

The motion of the ball is a projectile motion, so it is a parabolic motion with two independent motions:

- on the x-axis, a uniform motion with constant speed $v_x=12.0 m/s$

- on the y-axis, a uniformly accelerated motion with constant acceleration $a=9.8 m/s^2$ downward.

First of all, we need to find the time t at which the ball has travelled halfway to the chatcher, i.e. at a distance of $x=14.0/2=7.0 m$ . This can be found by using the relationship between distance, time and velocity along the horizontal direction: