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SIZIF [17.4K]
4 years ago
7

Dynamo converts the

Physics
2 answers:
Sav [38]4 years ago
6 0

Answer:

\gamma  \: dynamo \: converts \: the \: mechanical \: energy \: into \: electrical \: energy \: .

Explanation:

<em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>i</u></em><em><u>t</u></em><em><u> </u></em><em><u>h</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u>s</u></em><em><u> </u></em><em><u>y</u></em><em><u>o</u></em><em><u>u</u></em><em><u> </u></em><em><u>:</u></em><em><u>)</u></em><em><u>)</u></em><em><u>)</u></em>

Andre45 [30]4 years ago
5 0

Answer:

.

Explanation:

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4 points
zubka84 [21]

(a) 25lx

(b) 11.11lx

<u>Explanation:</u>

Illuminance is inversely proportional to the square of the distance.

So,

I = k\frac{1}{r^2}

where, k is a constant

So,

(a)

If I = 100lx and r₂ = 2r Then,

I_2 = k\frac{1}{(2r)^2}

Dividing both the equation we get

\frac{I_1}{I_2} = \frac{k}{r^2} X\frac{(2r)^2}{k} \\\\\frac{I_1}{I_2} = 4\\\\I_2 = \frac{I_1}{4}\\\\I_2 = \frac{100}{4}  = 25lx

When the distance is doubled then the illumination reduces by one- fourth and becomes 25lx

(b)

If I = 100lx and r₂ = 3r Then,

I_2 = k\frac{1}{(3r)^2}

Dividing equation 1 and 3 we get

\frac{I_1}{I_2} = \frac{k}{r^2} X\frac{(3r)^2}{k} \\\\\frac{I_1}{I_2} = 9\\\\I_2 = \frac{I_1}{9}\\\\I_2 = \frac{100}{9}  = 11.11lx

When the distance is tripled then the illumination reduces by one- ninth and becomes 11.11lx

3 0
3 years ago
Calculate the amount of gravitational potential energy at the top of each hill
Marizza181 [45]
The gravitational potential energy has the formula:
PE = mgh
where PE is in joules
m is the mass of the object in kg
g is the acceleration due to gravity
h is the height in m

since you did not give the value of h, i cannot fully answer your quesstion.
PE = (58/1000 kg) (9.81m/s2) h
PE = 0.57h
just substitute the value of h in the equation
5 0
4 years ago
A 2.2-m-long steel rod must not stretch more than 1.2 mm when it is subjected to a 8.5-kN tension force. Knowing that E = 200 GP
kodGreya [7K]

Answer:

a) 0.00996 m

b) 109090909 Pa

Explanation:

Unit conversions:

E = 200GPa = 200\times10^9 Pa

1.2 mm = 0.0012 m

8.5 kN = 8500 N

If the 2.2m rod cannot stretch more than 0.0012 m, its maximum strain is

\epsilon = \frac{\Delta L}{L} = \frac{0.0012}{2.2} = 0.000545455

With elastic modulus being E = 200 GPa, then its maximum stress must be

\sigma = E\epsilon = 200\times10^9*0.000545455 = 109090909 Pa

Knowing the tension force being F = 8500 N, we can calculate the appropriate cross section area

A = \frac{F}{\sigma} = \frac{8500}{109090909} = 7.79\times10^{-5}m^2

And its corresponding diameter is

A = \pi d^2/4

7.79\times10^{-5} = \pi d^2/4

d^2 = \frac{4*7.79\times10^{-5}}{\pi} = 9.92\times10^{-5}

d = \sqrt{9.92\times10^{-5}} = 0.00996 m \approx 1 cm

7 0
3 years ago
If a bowler rolls the bowling ball down the alleyway with a force of 1,000N. The ball exerts a reaction force again the alleyway
exis [7]
It’s 1,000 because it stays the same
3 0
3 years ago
Read 2 more answers
An important measure of LCD monitors is the time in milliseconds (ms) that it takes to turn a pixel on or off. What is this call
AleksandrR [38]

Answer:

Response Time

Explanation:

The time in milliseconds that LCD monitors takes to turn a pixel on or off is called Response time. A lower response time means that the LCD is able to cut down blurring or Ghosting of images thus producing better quality images.

Response time in general terms is the time interval that a system or a person takes to react to given input or event.

3 0
3 years ago
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