You know that ice floats in water. This is because

Physics

2 answers:

pochemuha4 years ago

7 0

A BECAUSE WHEN ITS MORE DENSE IT CAN FLOAT AND THE OTHER CHOICES DONT MAKE SENSE

AlladinOne [14]4 years ago

4 0

Anything that floats in some fluid must be less dense than the fluid.

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A cat rides a merry-go-round while turning with uniform circular motion. At time t1 = 2.00 s, the cat's velocity is v with arrow

DiKsa [7]

Answer:

(a)

$a_c=3.41\frac{m}{s^2}$

(b)

$a_a_v_g=0\frac{m}{s^2}$

Explanation:

Let's calculate the magnitude of cat's velocity at time t1 and time t2:

$At\hspace{3}t_1$

$|v_1|=\sqrt{(v_x)^{2}+(v_y)^{2} } =\sqrt{(1.70)^{2}+(4)^{2} } =4.346262762m/s$

$At\hspace{3}t_2$

$|v_2|=\sqrt{(v_x)^{2}+(v_y)^{2} } =\sqrt{(-1.70)^{2}+(-4)^{2} } =4.346262762m/s$

For now:

$|v_1|=|v_2|$

So, we can assume that cat's tangential velocity is constant. Now, considering that the time T required for one complete revolution is called the period. For constant speed is given by:

$T=\frac{2*\pi *r}{v}$ (1)

Where:

$r=radius\hspace{3}of\hspace{3}curvatrue$

$v=tangential\hspace{3}velocity$

The problem tell us that at time t2=4 the cat has completed a half-revolution, so we can conclude that the cat complete a revolution in 8s, T=8s. Replacing the data in (1) and isolating r:

$r=\frac{T*v}{2*\pi} =\frac{8*4.346262762}{2*\pi}=5.533833621m$