Answer:
7.34x
Explanation:
Depends on how long it was in the air. 7.34x, x is how many seconds.
The amount of work done in emptying the tank by pumping the water over the top edge is 163.01* 10³ ft-lbs.
Given that, the tank is 8 feet across the top and 6 feet high
By the property of similar triangles, 4/6 = r/y
6r = 4y
r = 4/6*y = 2/3*y
Each disc is a circle with area, A = π(2/3*y)² = 4π/9*y²
The weight of each disc is m = ρw* A
m = 62.4* 4π/9*y² = 87.08*y²
The distance pumped is 6-y.
The work done in pumping the tank by pumping the water over the top edge is
W = 87.08 ∫(6-y)y² dy
W = 87.08 ∫(6y³ - y²) dy
W = 87.08 [6y⁴/4 - y³/3]
W = 87.08 [3y⁴/2- y³/3]
The limits are from 0 to 6.
W = 87.08 [3*6⁴/2 - 6³/3] = 87.08* [9*6³ - 2*36] = 87.08(1872) = 163013.76 ft-lbs
The amount of work done in emptying the tank by pumping the water over the top edge is 163013.76 ft-lbs.
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C. A survey is asking people what they think is the answer.
The specific heat of aluminum is actually simply a
diversion. Because we can directly compute for the specific heat of copper
using the formula:
ΔH = m C ΔT
where ΔH is change in enthalpy or heat lost, m is mass, C
is specific heat and ΔT is change in temp
4,600 J = 150 g * C * (100 °C - 20°C)
C = 0.38 J/g°C
Answer:
Explanation:
Difference in the measurement by shuttle crew Δ d = 238857 - 226316 miles
= 12541 miles
Actual measurement = 238857 miles
percentage error
= (12541 / 238857 ) x 100
= 5.25 %
