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Goryan [66]
2 years ago
14

Increasing temperature increases solubility so that 480 grams (g) of sugar makes a saturated solution in 100 milliliters (mL) of

boiling water. If you add 240 g of sugar to 50 mL of boiling water, which will the solution be?
Physics
2 answers:
timofeeve [1]2 years ago
5 0
150 ml of saturated solution
Alexeev081 [22]2 years ago
5 0

Answer:

Salt

Explanation:

Rachel is given 50 grams each of three different white powders that look very similar. She is told that each of these powders is commonly used in cooking. Without tasting any of them, she is asked to try to identify them. She is told the amounts of sugar and salt that can each be dissolved in 100 mL of water. Substance Solubility (g per 100 mL water) table sugar 211 table salt 36 flour not soluble Rachel adds all 50 grams of one powder to 100 mL of water and stirs it for a while. Afterwards, she has a clear liquid with some powder on the bottom.  Which of the following could this powder have been?  A.  flour  B.  sugar  C.  salt  D.  all of these

that from Study ISLAND

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What is the relationship between power and voltage
FrozenT [24]

Answer

Voltage is how fast the electrons flow. Power is a use of voltage times the volumes of electrons. The higher the voltage the more power you have with the same current.

7 0
3 years ago
Below is a circuit schematic of sources and resistors (Figure 3). VS = 10V , R1 = 100Ω, R2 = 50Ω, R3 = 25Ω, IS = 2A. Calculate t
lorasvet [3.4K]

Answer:

V_3\approx 4.28\,\,V

I_1=0.0572\,\,amps

I_3\approx 0.171\,\,amps

Explanation:

Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.

So we first find the equivalent resistance for the two resistors in parallel:

\frac{1}{Re}= \frac{1}{R1}+\frac{1}{R2}\\\frac{1}{Re}= \frac{1}{100}+\frac{1}{50}\\\frac{1}{Re}= \frac{3}{100}\\Re=\frac{100}{3} \,\,\Omega

By knowing this, we can estimate the total current through the circuit,:

Vs=I\,*\,(\frac{100}{3} +25)\\10=I\,*\,\frac{175}{3} \\I=\frac{30}{175} \,amps

So approximately 0.17  amps

and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:

V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V

So now we know that the potential drop across the parellel resistors must be:

10 V -  4.28 V = 5.72 V

and with this info, we can calculate the current through R1 using Ohm's Law:

I_1=\frac{V_1}{R_1} =\frac{5.72}{100} =0.0572\,\,amps

4 0
3 years ago
Which statements describe properties of stars? Check all that apply.
Shtirlitz [24]
One, three and five are correct.

Although if the second statement is saying that stars use gravitational force to support nuclear fusion which in turn produces energy then that would be correct, but I don’t think so :)
7 0
3 years ago
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A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C. How much water freezes onto the ice? The specific heat of
vladimir2022 [97]

For A 53 g ice cube at −30◦C is dropped into a container of water at 0◦C, the amount of water that freezes onto the ice?  is mathematically given as

x = 9.93 g

<h3>What is the amount of water that freezes onto the ice?</h3>

Where

Energy received = energy given out

Generally, the amount of water is mathematically given as

(53)(0.5)(30) = (80)(x)

Therefore

x = (49)(0.5)(16)/(80)

x = 9.93 g

In conclusion, the mass of water

x = 9.93 g

Read more about  mass

brainly.com/question/15959704

4 0
2 years ago
When an ideal diatomic gas is heated at constant
ira [324]

Answer:

Q=∆U+W

Explanation:

work done+ change in internal energy = heat supplied to change the internal energy

(1st law of thermodynamics)

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