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vovikov84 [41]
3 years ago
9

A mountain climber is at an altitude of 2.9 mi above the earths surface. From the climbers viewpoint what is the distance to the

horizon

Mathematics
1 answer:
andriy [413]3 years ago
6 0
We know that
<span>applying the Pythagorean theorem
(3959+2.9)</span>²=x²+3959²
x²=(3959+2.9)²-3959²
x²=3961.9²-3959²
x²=22970.61
x=√22970.61
x=151.56 mi

the answer is
x=151.56 mi
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Pythagorean theorem
Talja [164]

Answer:

b=20 yards

Step-by-step explanation:

15^2+x^2=25^2

225+x^2=625

x^2=400

x=20

5 0
3 years ago
5 less than the quotient of a number y and 2
Marta_Voda [28]
Quotient means division....less then means subtract
(y/2) - 5
5 0
3 years ago
Cylinder E has the following dimensions: h = 30 cm and r = 4 cm. Cylinder F has the same radius, but has a height of 5 cm . What
Anarel [89]

Answer:

1759.52cm^3

Step-by-step explanation:

Given data

Cylinder E

h = 30 cm and

r = 4 cm

The expression for the volume is

V= πr^2h

V= 3.142*4^2*30

V= 3.142*16*30

V=1508.16 cm^3

Cylinder F

h=5 cm

r = 4 cm

The expression for the volume is

V= πr^2h

V= 3.142*4^2*5

V= 3.142*16*5

V=251.36 cm^3

Hence the total volume is

=251.36+1508.16

= 1759.52cm^3

6 0
3 years ago
A total of 937 people attended the play.
insens350 [35]

Answer:

1.75

c

+

2.25

a

=

1083.00

now we still know, that

a

=

508

−

c

so we can substitute it into the second formula

1.75

c

+

2.25

(

508

−

c

)

=

1083

now its just simple algebra

1.75

c

+

1143

−

2.25

c

=

1083

60

=

0.5

c

so:

c

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Step-by-step explanation:

6 0
3 years ago
Circle O and triangle OQR are shown below. What is the length of OQ?
zysi [14]

Answer:

Step-by-step explanation:

A circle is inscribed in an equilateral triangle PQR with centre O. If angle OQR = 30°, what is the perimeter of the triangle?

This is a circle inscribed in an equilateral triangle with side s.

If you are asking for the perimeter of PQR, it is 3s.

If you are asking for the perimeter of OQR, it is (3+23–√3)s

Since OR and SR are the hypotenuses of right triangles with adjacent side equal to ½ s, their length is ½s / cos 30° = (√3) /3.

(3/3)s + ((√3) /3)s + ((√3) /3)s = ((3 + 2√3)/3)s ≈ 2.1547s

Hope it helps

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3 0
2 years ago
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