I just answered this question. Here's my answer
Given:
Perimeter of KLMN = 42
h1 = 5
h2 = 6
Based on the given figure here are my assumptions.
1) KLMN is a parallelogram
2) h1 and h2 are long legs of right triangles.
3) the right triangles are similar but not congruent.
Perimeter of a parallelogram = 2(a+b)
a = KL ; b = LM
Area of a parallelogram = bh
b = LM ; h = h1
We need to find the values of a and b to solve for the Area of KLMN.
LM and KL are hypotenuse of its own right triangle. Similar triangle means that their proportion are equal.
P = 2(a+b)
42 = 2(a+b) → 42/2 = a+b → 21 = a + b → 21 - a = b
hypotenuse/long leg
a/5 = b/6 → a/5 = (21-a)/6 → a*6 = 5(21-a) → 6a = 105 - 5a
6a + 5a = 105 → 11a = 105 → a = 105/11 → a = 9.55
b = 21 - a → b = 21 - 9.55 → b = 11.45
Area of parallelogram = bh
A = 11.45 * 5
<span>A = 57.25 square units.</span>
Answer:
-6 1/4
Step-by-step explanation:
2(8x - 1) + 7(x + 5) = -59 Distribute/multiply 2 into (8x - 1), and multiply 7 into (x + 5)
16x - 2 + 7x + 35 = -59 Combine like terms
23x + 33 = -59 Subtract 33 on both sides
23x = -92 Divide 23 on both sides
x = -4
[proof]
2(8x - 1) + 7(x + 5) = -59
2(8(-4) - 1) + 7(-4 + 5) = -59
2(-32 - 1) + 7(1) = -59
2(-33) + 7 = -59
-66 + 7 = -59
-59 = -59
Answer:
32 sq ft.
Step-by-step explanation: