Here we have to get the alcohols which are formed in the reaction of an alkene with H₂SO₄ and H₂O.
The alcohols which are formed in the reaction between alkene and H₂SO₄ and H₂O are majorly secondary and tertiary alcohol. As primary alcohol only ethanol can be produced in this reaction.
The addition of H₂SO₄/H₂O generates alcohol from alkene. The general reaction is shown in the figure. In this reaction methanol (CH₃OH) cannot be prepared and in primary alcohol only ethanol (C₂H₅OH) can be prepared from ethene.
In case of propene and other higher alkene always secondary or tertiary alcohols are produced as the addition of sulphuric acid and water depends on the Markonikov's rule of addition to the less hindered position.
Data:
p = 1 atm
V = 10 m * 8 m * 5 m = 400 m^3 = 400,000 liter
To = 0 + 273.15K = 273.15K
Tf = 20 + 273.15K = 293.15K
No - Nf =?
2) Formula
pV = NRT => N = pV / (RT)
3) solution
No = pV / (RTo)
Nf = pV / (RTf)
=> No - Nf = [pv / R] [ 1 / To - 1 / Tf ]
=> No - Nf = [1atm*400,000liter / 0.0821 atm*liter/K*mol ] [ 1 / 273.15 - 1 / 293.15]
No - Nf = 1216.9 moles ≈ 1217 moles
Answer: 1217 moles
<h2><u>Answer:</u></h2>
A nonpartisan iota of Nitrogen has a mass of 18. There are 7 protons in the core of this iota. What number of neutrons, complete electrons, and valence electrons are available
Nitrogen 15 has a nuclear mass of 15. The mass number is # protons in addition to # of neutrons, so for N-15 mass is 15 and the protons are dependably 7 so there must be 15-7=8 neutrons. N-15 has 7 electrons since it has 7 protons and p = e.
Answer:
1:2
Explanation:
For every 4 moles of aluminum, there are 2 moles of aluminum oxide, so the mole ratio when converting from aluminum to alunmimum oxide is
2 moles aluminum oxide:4 moles aluminum. This can be simplified to 1:2.
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Answer:
False
Explanation:
It is psychological for you do not depend on it to live.