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earnstyle [38]
3 years ago
7

How many grams are there in 2.3*10^24 atoms of silver nitrate ?​

Chemistry
1 answer:
Paul [167]3 years ago
6 0
410g Ag

2.3*10^24 atoms

1 molcule Ag- 6.02g*10^3
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07.

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Answer:

a) The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

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Molar Concentration =  \frac{mole \ \ of \ soulte }{ Volume \ of \ solution }

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