1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Crazy boy [7]
3 years ago
12

If you know the number of protons, how do you find the number of electrons

Chemistry
1 answer:
iren [92.7K]3 years ago
4 0

Answer:

to find the number of electrons you need the charge of the element.

You might be interested in
What is the density of a block of marble that occupies 277 cm3 and has a mass of 928 g? Answer in units of g/cm3 .
Evgesh-ka [11]
V=277cm^{3}\\
m=928g\\\\
d=\frac{m}{V}=\frac{928g}{277cm^{3}}\approx3,35\frac{g}{cm^{3}}
8 0
3 years ago
What must occur in order for a chemical reaction to be specifically classified as endothermic instead of exothermic?
Alla [95]

Answer:  B- Chemical bonds are formed. Energy is released in the form of heat.

Explanation: I hoped that helped !

6 0
3 years ago
Read 2 more answers
Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a
GrogVix [38]

Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

8 0
2 years ago
If an atom has the same equal amount of electron and proton is it charged or uncharged ​
Doss [256]

Answer:

Neutral or uncharged

Explanation:

The positive charge on a proton is equal in magnitude to the negative charge on an electron. As a result, a neutral atom must have an equal number of protons and electrons.

3 0
2 years ago
Read 2 more answers
The mass of a quantity of NiCl2
Gennadij [26K]
Not sure, is it <span>:
</span>B.
<span> 1.9 3 1027 NiCl2
formula units</span>
3 0
3 years ago
Read 2 more answers
Other questions:
  • Help, cant get it. Answers in picture
    11·1 answer
  • A student determined that the weight-percent recovery for his isolated caffeine proved to be 1.5%. The student was concerned, ex
    11·1 answer
  • Express 0.08010 in exponential notation to the proper significant figures
    11·1 answer
  • A solution of 0.207 M aspartic acid, the charge neutral form of the amino acid, is titrated with 0.0690 M NaOH . The pKa values
    9·1 answer
  • Predict whether each of the following substances would be more soluble in water (polar solvent) or in a hydrocarbon such as hept
    9·1 answer
  • What is the most common climate in Brazil? A, B, C, or, D
    9·1 answer
  • State 2 ways in which adaptation help animals?
    9·1 answer
  • How can you express the rate of a chemical reaction
    12·1 answer
  • Explain how light is produced in neon signs.
    9·2 answers
  • I need help on science lol.
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!