Answer : The molar volume of the gas will be, 44.82 L
Solution :
Using ideal gas equation,
where,
n = number of moles of gas = 1 mole
P = pressure of the gas = 0.5 atm
T = temperature of the gas = 273 K
R = gas constant = 0.0821 Latm/moleK
V = volume of the gas.
Now put all the given values in the above equation, we get the molar volume of the gas.
Therefore, the molar volume of the gas will be, 44.82 L
Answer:
5.66g/ml
Explanation:
Mass of Metal Slug, m = 25.17g
Volume of container (flask), v = 59.7ml
Mass of Methanol, M = 43.7g with density, d = 0.791g/ml
Therefore,
Volume of Methanol = M/d = 43.7 / 0.791 = 55.25ml
Volume of Metal slug in the flask = v - V = 59.7 - 55.25 = 4.45ml
Density of Metal slug = mass of metal slug / volume of metal slug
= 25.17 / 4.45 = 5.66g/ml
1 gram of HNO3 will be equal to 1/63.01 moles. Therefore, we can say that 1 liter of Nitric acid contains 15.6976 moles or in other words molarity of 70% (w/w) Nitric acid is equal to 15.6976 M.
Known values
Molecular weight of HNO3 63.01 g/mole
Concentration of Nitric acid 70% (% by mass, wt/wt)
Zwitterion is an ion consists of equal positive and negative charges on the same molecule which make it more stable and has high melting point
p-aminobenzene sulfonic acid contains both acidic (-SO₃H) and basic groups (NH₂), the acidic group will lose one proton to give (-SO₃⁻) and the basic group will gain this proton to give (-NH₃⁺)
The structure is:
n=20 mol
(NH)4 SO4
Atomic masses :
N- 14
H- 1
S- 32
O- 16
Therefore M= 14×2 + 1×8 + 32 + 16×4
= 132
m= nM
= 20×132
= 2640g
