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sesenic [268]
3 years ago
10

A puddle of water on the porch disappears after a few days. Which statement justifies this phenomenon?

Chemistry
1 answer:
scoundrel [369]3 years ago
7 0
Condensation...hope this is an option

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Potassium bromide conducts electricity when ______
amm1812

Answer:

When melted or dissolved in water.

Explanation:

Potassium bromide in its solid form contains ions, which are charged atoms. Through the heating process, the melted potassium bromide becomes an ionic liquid. If solid potassium bromide is dissolved, for example in water, the resulting release of ions allows it to conduct electricity.

3 0
3 years ago
Which of these does not cause a change in the reaction rate?
VMariaS [17]
A. density
<span>Reaction rate increases with concentration.</span>
8 0
3 years ago
Read 2 more answers
How many Liters are there in 51. 300 cm? (11 = 1000 cm)
Black_prince [1.1K]

Answer:

4,572.67

Explanation:

11 divided by 1000= 90.90

44= 11x

x=4

4 x 11= 4000

44-51.300=6.300

6.300 x 90.90=572.67

4000 + 572.67 = the answer

7 0
3 years ago
how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate
Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})

= 95.7gNaClO_3

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate  and then the grams are converted to kg.

95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

7 0
3 years ago
Determine the volume of an object that has a mass of 455.6 g and a density of 19.3 g/cm3. (1cm3 = 1ml) select one:
Dmitry [639]
The answer is B. The density, or more precisely, the volumetric mass density, of a substance is its mass per unit volume.

4 0
3 years ago
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