Who Invented microscopes? (This one is for fun. I will be giving away 50 points to the first person!)

Chemistry

1 answer:

Liula [17]3 years ago

6 0

Zacharias Janssen invented the microscope.

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What mass of sodium chloride contains 4.59 x 10 24 formula units?

shtirl [24]

The term formula units means molecules.

Then, what you are looking for is the mass in 4.59*10^24 molecules.

The procedure involves to convert the 4.59 * 10^24 molecules into moles and use the molar mass of the sodium chloride.

1) Number of moles = 4.59 * 10^24 molecules / (6.02 * 10^23 molecules/mol) = 7.62 mol

2) Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

3) mass of NaCl = molar mass * number of moles = 58.44 g/mol * 7.62 mol = 445.31 g of NaCl

Answer: 445.31 g of NaCl.

7 0

3 years ago

the volume of gas in a container was originally 3.24L, while at standard pressure 1.00 atm. what will the volume be if the press

Simora [160]

Hello!

To solve this problem, we will use the Boyle's Law, which describes how pressure changes when volume changes and vice-versa. The equation for this law is the following one, and we'll clear for V2:

$P1*V1=P2*V2 \\ \\ V2= \frac{P1*V1}{P2}= \frac{3,24 L * 1 atm}{1,20 atm}= 2,7 L$

So, the final volume after increasing the pressure would be 2,7 L. That means that volume decreases when the pressure increases

Have a nice day!

8 0

3 years ago

Can you Please answer this question?

olga2289 [7]

Answer:

first option is not true

Explanation:

1 mole = 6.02 × 10²³ particles

C3H8 has 1 mole, so has 6.02 × 10²³ particles

5O2 has 5 moles so 5 × 6.02 × 10²³ = 3.01 × 10²⁴ particles

3CO2 has 3 moles so 3 × 6.02 × 10²³ = 1.806 × 10²⁴ particles

4H2O has 4 moles so 4 × 6.02 × 10²³ = 2.408 × 10²⁴ particles

8 0

2 years ago

Which of these is a chemical property of a substance?

Ghella [55]

Flamability boiling point color

3 0

3 years ago

Read 2 more answers

When 5.00 mol of benzene is vaporized at a constant pressure of 1.00 atm and at its normal boiling point of 80.1°C, 169.5 kJ are

NNADVOKAT [17]

Answer:

∆E=155kJ

Explanation:

Check attachment

3 0

3 years ago