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4 years ago

A diffusion coefficient KG was determined for the diffusion of a gas A through a stagnant film B [KG = 0.88 mol//h-ft2-atm].

Chemistry

1 answer:

Angelina_Jolie [31]4 years ago

4 0

Explanation:

Transfer of mass A into stagnant film B depends on the availability of driving force.

Whereas driving force is the pressure difference at the surface of A and the bulk.

As, $N_{A} \propto (P_{A1} - P_{A2})$

$N_{A} = K_{G} \times (P_{A1} - P_{A2})$

Therefore, putting the given values into the above formula as follows.

$N_{A} = K_{G} \times (P_{A1} - P_{A2})$

= $0.88 \times (0.2 atm - 0.05 atm)$

= 0.132 $mol/h.ft^{2}$

Thus, we can conclude that the flux of A from a surface into a mixture of A and B is 0.132 $mol/h.ft^{2}$

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You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from

GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $200mL+200L=400mL$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 400 g

$T_{final}$ = final temperature of water = $27.78^oC=273+25.10=300.78K$

$T_{initial}$ = initial temperature of metal = $25.10^oC=273+27.78=298.1K$

Now put all the given values in the above formula, we get:

$q=400g\times 4.18J/g^oC\times (300.78-298.1)K$

$q=4480.96J$

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

$\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

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3 years ago

If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, what be

Sergio [31]

Well, keep in mind q=msΔT, and that in these sorts of questions, -msΔT = msΔT (meaning that the energy lost by the metal as it cools down is gained by the water as it heats up).

If you put something hot into something cold, what happens? The hot metal would cool down, while the water would heat up, and given some time, both the metal and water would be at the same temperature. The metal would have cooled down, while the water would have heated up.

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3 years ago

What conditions are important in determining if it will rain or snow?

zhannawk [14.2K]

For snow to fall to the ground, the temperature must be cold both up in the clouds where snowflakes form, and down at ground level. If the air near ground level is too warm, the snow will melt on its way down, changing to rain or freezing rain. Moisture is needed to form clouds and precipitation.

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3 years ago

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Can someone please explain how to do number 11?

BaLLatris [955]

Answer:

HBr + Mg(OH)2 —> MgBr2 + H2O.

To balance the above, we must do a head count of the individual atoms present to ensure they balance on both sides of the equation. To get the balance equation, add 2 in front of HBr and 2 in front of H2O as shown below:

2HBr + Mg(OH)2 —> MgBr2 + 2H2O

We can see clearly that the numbers of the individual atoms on the left side is the same on the right side

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4 years ago

Which statement is true? 1. The electronegativity of an atom depends only on the value of the ionization energy of the atom. 2.

lisov135 [29]

Answer:

5. Atoms with high ionization energies and high electron affinities have low electronegativities.

Explanation:

Ionization energy is the minimum amount of energy which is required to knock out the loosely bound valence electron from the isolated gaseous atom.

Electron affinity is the amount of energy released when an isolated gaseous atom accepts electron to form the corresponding anion.

Electronegativity is the tendency of an atom in a bond pair to attract the shared pair of electron towards itself.

Low ionization energies as well as low electron affinities mean the atom has low effective nuclear charge, which results in the less attraction of the valence electrons by the atom and thus, low electronegativity.

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3 years ago