Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
25%. 60 divided by 15 is 4, thus 15 is 1/4 of 60. 1/4 can also be expressed as 25%
Answer:
1 in 12 chance of landing on 3
1 in 12 chance of landing on 4
1 in 6 chance of landing on either 3 or 4
Step-by-step explanation:
12 equal sections means probability is 1 in 12 of landing on any one numbered section.
2 in 12 or 1 in 6 chance of landing on either of two numbered sections in one attempt.
Answer:
(Answer D)
Step-by-step explanation:
Please use " ^ " to indicate exponentiation: y = -8x^2 - 2, y = -8x^2
The graph of y = -8x^2 is an inverted parabola with vertex at (0, 0).
That of y = -8x^2 - 2 is the same as above, except that the whole graph has been shifted 2 units down (Answer D).
So, the first thing you want to find out is how many seconds each person adds to the wait time. Find out how many seconds are in 20 minutes.. 20*60=120. 120/150=0.8 seconds. Each person adds 0.8 seconds to the wait time. Now, multiply that by 240.. 240*0.8=192 seconds. Lastly, find out how many minutes 192 seconds is... 192/60=32 minutes.
I hope I did that right! And if I did, I hope that helped!
