Can someone give me the units

Suppose the average mass of each of 20,000 asteroids in the solar system is 1017 kg. Compare the total mass of these asteroids t

blondinia [14]

Answer:

The mass of the asteroids is 0.000334896182184 times the mass of the Earth.

39929.4542466 m

Explanation:

Total mass of the asteroids

$m_a20000\times 10^{17}=2\times 10^{21}\ kg$

$m_e$ = Mass of Earth = $5.972\times 10^{24}\ kg$

The ratio is

$\dfrac{m_a}{m_e}=\dfrac{2\times 10^{21}}{5.972\times 10^{24}}\\\Rightarrow \dfrac{m_a}{m_e}=0.000334896182184$

The mass of the asteroids is 0.000334896182184 times the mass of the Earth.

Volume is given by

$V=\dfrac{m}{\rho}\\\Rightarrow \dfrac{4\pi}{3\times 8} d^3=\dfrac{m}{\rho}\\\Rightarrow d^3=\dfrac{3\times 8}{4\pi}\dfrac{m}{\rho}\\\Rightarrow d=(\dfrac{3\times 8}{4\pi}\dfrac{m}{\rho})^{\dfrac{1}{3}}\\\Rightarrow d=(\dfrac{3\times 8}{4\pi}\dfrac{10^{17}}{3000})^{\dfrac{1}{3}}\\\Rightarrow d=39929.4542466\ m$

The diameter is 39929.4542466 m

6 0

3 years ago

When a ray of light passes at an angle to the normal from one material into another material in which its speed is higher?

Gnesinka [82]

I think your talking about refraction and if so the first medium it existed in before entering the second usually has the higher speed especially it the first medium is less denser than the second

4 0

4 years ago

A student pushes a 10 kg box with a force of 30 N at an angle 45 degrees below the horizontal . The box experi 21.2 N of force a

Shkiper50 [21]

Answer:

Acceleration =0

Explanation:

There are two forces on the box in horizontal direction.

First one is horizontal component of 30N at 45°.

$F=\frac{1}{\sqrt{2} }*30=21.2$

Another one is given in opposite to direction of motion mean opposite to this force.

Which is = 2.22 N

Now we know F (net) =mass*acceleration(center of mass)

21.2-21.2 =10*acceleration

acceleration =0

6 0

4 years ago

What is average velocity

Sphinxa [80]

Answer:

Average velocity is the displacement of an object over time that also in a specified direction...

Explanation:

brainliest plz

6 0

3 years ago

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to en

Nina [5.8K]

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

$dl'=3.621*10^{-4}m$

From the question we are told

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Generally the equation for copper cylinder is mathematically given as

$dl=\frac{Flo}{yA}$