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s2008m [1.1K]
3 years ago
5

To measure the strength of an earthquake, you can use either a _____ scale or _____ scale.

Physics
2 answers:
allsm [11]3 years ago
8 0
To measure the strength of an earthquake, you can use either a Richter scale or Mercalli scale. Richter scale uses the amplitued of the wave and the distance from the source. Mercalli scale uses observations of people and is not considered to be scientific as Richter scale.
Shalnov [3]3 years ago
7 0

Earthquakes are measured with the Richter Magnitude Scale developed by Charles F. Richter of California Institute of Technology in 1935. Here is a summary of the Richter scale:

Magnitude less than 3.5: Generally not felt, but recorded.

Magnitude 3.5-5.4: Often felt, but rarely causes damage.

Magnitude under 6.0: At most slight damage to well-designed buildings over small regions.

Magnitude 6.1-6.9: Can be destructive in areas up to 100 kilometers across where people live.

Magnitude 7.0-7.9: Major earthquake. Can cause serious damage over larger areas.

Magnitude 8 or greater: Great earthquake. Can cause serious damage in areas several hundred kilometers across.

Earthquakes are also measured by the Mercalli Intensity Scale which is a longer, more detailed scale. Both the Richter Scale and the Mercalli Scale can be seen on the U.S. Geological Survey website.



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List the following types of electromagnetic radiation in order of increasing wavelength:(i) the gamma rays produced by a radioac
Naddik [55]

Answer:

In order of increasing wavelength, the answer is:

(i) The gamma rays produced by a radioactive nuclide used in medical imaging

(iv) The yellow light from sodium-vapor streetlights

(v) The red light of a light emitting diode, such as in a calculator display

(ii) Radiation from an FM radio station at 93.1 MHz on the dial

(iii) A radio signal from an AM radio station at 680kHz on the dial

Explanation:

First, you have to know that the wavelength of a sinusoidal wave traveling at a constant speed is given by:  

                                       λ = \frac{v}{f}

Where λ is the wavelength, v is the constant speed and f is the wave's frequency. In the case of electromagnetic radiation in free space, the constant speed is the speed of light.

From explained above, you can conclude that there is a proportionality relationship between the wavelength and the frequency, they are inversely proportional. That means: the highest frequency will have the shortest wavelength and vice-versa.

So, you have the following types:

(i) The gamma rays produced by a radioactive nuclide used in medical imaging

Frequency : Typically greater than 10^{19} Hz

(ii) Radiation from an FM radio station at 93.1 MHz on the dial

Frequency: 93.1 MHz

(iii) A radio signal from an AM radio station at 680 kHz on the dial

Frequency: 680 kHz

(iv) The yellow light from sodium-vapor streetlights

Frequency: Visible spectrum of approx. 508 - 526 THz

(v) The red light of a light-emitting diode, such as in a calculator display

Frequency: Visible spectrum of approx. 400 - 484 THz

Then, you have to organize them from the highest frequency to the smallest one (decreasing frequency), and as the highest frequency will have the shortest wavelength, you are going to have it organized in an increasing wavelength mode.

Then in order of increasing wavelength, the answer will be:

                                           (i) , (iv), (v), (ii), (iii)

3 0
3 years ago
An electron (q=-1.602×10-19C) is placed .03m away from spherical object with a net charge of -7.2 C.
vovangra [49]

Answer:

Explanation:

electric field at the location of electron

= 9 x 10⁹ x 7.2 / .03²

= 72 x 10¹² N/C

force on electron = electric field x charge on electron

= 72 x 10¹² x 1.6 x 10⁻¹⁹

= 115.2 x 10⁻⁷ N .

C )

work done = charge on electron x potential difference at two points

potential at .03 m

= 9 x 10⁹ x 7.2 / .03

= 2.16 x 10¹² V

potential at .001 m

= 9 x 10⁹ x 7.2 / .001

= 64.8 x 10¹² V

potential difference = (64.8 - 2.16 )x 10¹² V

= 62.64 x 10¹² V  .

work done = 62.64 x 10¹² x 1.6 x 10⁻¹⁹

= 100.224 x 10⁻⁷ J .

D )

There will be no change in the magnitude of force on positron except that the direction of force will be reversed . In case of electron , there will be repulsion and in case of positron , there will be attraction .

Work done in case of electron will be positive and work done in case of positron will be negative .

electric field due to charge will be same in both the cases .

8 0
3 years ago
Which conditions must be met in order for work to be done?​
Anettt [7]

Answer:

u wanna do my edge bro the answer is b

Explanation:

3 0
3 years ago
Which are most likely to be used during a routine visit to the dentist?
Paraphin [41]

Answer:

The most likely items to be used are;

Ultrasound and X-rays

Explanation:

A routine visit to a dentist consists of two areas of activities, including;

a) Dental examination and check up

b) Oral prophylaxis, and dental cleaning

The dental examination may involve the use of X-rays, which allow the detection of cavities between the teeth

The dental cleaning can be carried out with the use of an ultrasound cleaner, which allow the cleaning of sensitive teeth without hurting the patient

Therefore, the items most likely to be used during a routine dental visit are ultrasound and X-rays

8 0
3 years ago
Read 2 more answers
What is difference between magnetic flux and magnetic flux linkage?​
Anika [276]

Answer:

Magnetic flux has formular: BA while Magnetic flux linkage has formula: NBA

Explanation:

N is number of turns of a coil

B is magnetic flux density across the coil

A is area of coil

.

7 0
2 years ago
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