The distance between the two charges is 
Explanation:
The electrostatic force between two charged objects is given by Coulomb's law:
where:
is the Coulomb's constant
are the charges of the two objects
r is the separation between the two charges
In this problem, we are given the following:
Therefore, we can rearrange the equation to solve for r, the distance between the two charges:
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<span>Mass of the electron = 9.1 x 10 ^ -28g = 9.1 x 10 ^ -31kg
Velocity of the electron = 1.7 x 10 ^ 4
We have Planck Constant h = 6.626 x 10 ^ -34
Wavelength of the electron w = h/mv
w = 6.626 x 10 ^ -34 / ((9.1 x 10 ^ -31)(1.7 x 10 ^ 4))
= 6.626 x 10 ^ -34 / 15.47 x 10 ^ -27
= 0.428312 x 10 ^ -7
= 4.28 x 10 ^ -8 m</span>
Answer:
Explanation:
In equilibrium , weight of mug is equal to restoring force .
mg = kx where m is mass of mug , k is spring constant and x is extension .
k / m = g / x = 9.8 ms⁻² / .025 m
= 392
frequency of oscillation n = 
= 4.46 per second.
Answer:
Explanation:
The relationship between the refractive index and the critical angle is given as follows:
where,
η = refractive index = 1.67
θc = critical angle =?
Therefore,
The momentum of the bumper car after the collision is 1,040 kgm/s.
<h3>
Momentum of bumper</h3>
The change in momentum of the bumper is calculated as follows;
P = v(m1 + m2)
P = 8(55 + 75)
P = 1,040 kgm/s
The momentum of the bumper car after the collision is 1,040 kgm/s.
The direction is still the same.
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