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Lana71 [14]
3 years ago
8

A carmaker has designed a car that can reach a maximum acceleration of 12 meters/second2. The car’s mass is 1,515 kilograms. Ass

uming the same engine is used, what should the car’s mass be if the carmaker wants to reach an acceleration of 15 meters/second2? Use F = ma.
A 1,212 kg
B 1,335 kg
C1,466 kg
D 1,515 kg
D 1,894 kg
Physics
1 answer:
Vlada [557]3 years ago
6 0
1) 15 / 12 = 1.25 ratio
2) to increase acceleration  1.25 times (with same F, or same engine) you have to lower mass 1.25 times
3) 1515/1.25 = 1212 kg

choose A

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Two identical vertical springs S1 and S2 have masses m1 = 400 g and m2 = 800 g attached to them. If m1 causes spring S1 to stret
OlgaM077 [116]

Answer:

potential energy = mgh

= 400÷1000 × 10× 4÷100

= 0.4 × 10 × 0.04

=4/10 ×10×4/100

= 4/10 × 4/10

=16/100

= 0.16 joules

m1 (400) stretches 4cm

m1 (100g) stretches 1cm

so, m2(800g) stretches 8 cm

potential energy of m2 = mgh

= 800/1000 ×10×8/100

= 0.8 × 0.8

=8/10 ×8/10

= 64/100

=0.64 joules

Ratio of s1 to s2

16/100 ÷ 64/100

= 1:4 ( answer)

6 0
2 years ago
Help me plz i don’t know the charges on each of these
ivanzaharov [21]

Object B is positively charged, Object C is negatively charged, Object D is negatively charged.

4 0
3 years ago
I am a bit confused about this question.
gavmur [86]

How do you know when something is moving ?  You ALWAYS have to compare it to something else.  If the object in question changes its distance or direction from your house, or from your big toe, or from a stake in the ground in your front yard, then you say it's moving.  The thing is:  There's ALWAYS something else to compare it to.

I assume you're sitting on the couch now, staring at the TV, or at your computer, or at your phone.  Compared to the couch, or to the tree in your front yard, or to somebody sitting on top of Mt. Everest, or to downtown Jerusalem, you're NOT moving.  Your distance and direction from the reference point isn't changing.

BUT ... what if you compare yourself to somebody sitting at the North pole of the Sun ?  He has to keep turning his eyes to watch you (because the Earth including you is in orbit around the sun).  So your direction from him keeps changing, and 'relative' to him (compared to him), you're definitely moving.

Now let's go a little farther:  

You're sitting in a comfy seat, reading a book that's in your lap.  Maybe you're even getting sleepy.  You're sitting still in the seat, and the book in your lap isn't moving.

SURPRISE !  Your comfy seat is in Row-27 of a passenger jet, and you're flying to Seattle to visit your Grandma.  right now, you're just passing over Casper, Wyoming, and there's somebody down on the ground playing with a telescope.  He looks at your airplane, and HE says that you, the seat you're sitting in, and your book are ALL moving at almost 500 miles an hour.

The difference is:  YOU're comparing your book to the seat in front of you, and YOU say the book is not moving.  The guy with the telescope is comparing the book to the ground he's standing on, and HE says your book is moving west at 500 miles an hour.

You're BOTH correct.  The description of ANY motion always depends on what you're comparing to.  If you're about to ask "What's the REAL motion of the book ?", then I'm sorry.  There's NO SUCH THING as 'REALLY'.  It always depends on what you're comparing to.  Nine people can be watching the same object, and they can have nine different descriptions of its motion, and they're ALL correct.  They're just comparing the object to different things in their own neighborhood, and the nine things are all moving in different ways.

The bottom line:  MOTION IS ALWAYS RELATIVE (to something else).

8 0
3 years ago
A 150 g sample of brass at 100 °C is placed in a Styrofoam cup of water containing 120 mL of water at 10 °C. No heat is lost to
fredd [130]

Answer:

≈19.144°C.

Explanation:

all the details are in the attachment.

Note, that c₁, m₁, t₁ are the parameters of the sample of brass; c₂, m₂ and t₂ are  the parameters of the sample of water.

P.S. change the provided design according Your requirements.

4 0
2 years ago
While dragging a crate a workman exerts a force of 628 N. Later, the mass of the crate is increased by a factor of 3.8. If the w
Delvig [45]
Force applied = F = 628 N 
<span>Acceleration = a m/s² </span>
<span>Newton's 2nd law of motion : F = Ma </span>
<span> a = F/M -------- (1) </span>
<span>New mass of the crate = M1 = 3.8M kg </span>
<span>New acceleration = a1 = F/M1 = F/(3.8 M) ----- (2) </span>
<span>a1/a = {F/(3.8M)}/(F/M) = 1/3.8 = 10/38 = 5/19 ------- Answer</span>
6 0
4 years ago
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