Answer:
∴ The absolute pressure of the air in the balloon in kPa = 102.69 kPa.
Explanation:
- We can solve this problem using the general gas law:
<em>PV = nRT</em>, where,
P is the pressure of the gas <em>(atm)</em>,
V is the volume of the gas in L <em>(V of air = 6.23 L)</em>,
n is the no. of moles of gas <em>(n of air = 0.25 mole)</em>,
R is the general gas constant <em>(R = 0.082 L.atm/mol.K)</em>,
T is the temperature of gas in K <em>(T = 35 °C + 273 = 308 K</em>).
∴ P = nRT / V = (0.25 mole)(0.082 L.atm/mol.K)(308 K) / (6.23 L) = 1.0135 atm.
- <em>Now, we should convert the pressure from (atm) to (kPa).</em>
1.0 atm → 101.325 kPa,
1.0135 atm → ??? kPa.
∴ The absolute pressure of the air in the balloon in kPa = (101.325 kPa)(1.0135 atm) / (1.0 atm) = 102.69 kPa.
<span>1. Gaseous acetylene (C2H2) reacts with oxygen gas to form gaseous carbon dioxide and gaseous water.
2. Chlorine gas reacts with aqueous potassium iodide to form solid iodine and aqueous potassium chloride.
3. Solid lithium oxide reacts with liquid water to form aqueous lithium hydroxide.
4. Gaseous carbon monoxide reacts with oxygen gas to form carbon dioxide gas.</span>
Lead: Pb, oxygen: O, and silver: Ag
The answers to this question is b, I did this on Plato
<span>68g since 34/100 is 34 right?
so if you have 200g of H2O you can put in twice as much KCl
so it is 68g</span>
