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IRISSAK [1]
3 years ago
8

A student increases the temperature of a 200cm3 balloom from 60 degress C to 180 degrees C. What will the new volume of the ball

oon be? (Be careful with units)
600cm^3
100cm^3
236cm^3
272cm^3
Chemistry
1 answer:
kkurt [141]3 years ago
4 0

Answer:

The new volume of the balloon is 600cm³

Explanation:

Given parameters:

Initial Volume, which is V₁ = 200cm³

Initial temperature, T₁ = 60°C

Final temperature T₂ = 180°C

Final Volume V₂ =?

To solve this kind of problem, we apply one of the gas laws that shows the relationship between volume and temperature.

This law is the Charles law, it states that " the volume of a fixed mass of a gas is directly proportional to its absolute temperature if pressure is constant".

It is simply expressed as:

V₁/T₁ = V₂/T₂

Since our unknown is V₂, we make it the subject of the expression given above:

V₂ = V₁T₂/T₁

Now input the corresponding values and solve:

V₂ = 200 x 180 / 60

V₂ = 36000/60

V₂ = 600cm³

The new volume of the balloon is 600cm³

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3 years ago
STATES THAT FOR AN ATOM IN THE GROUND STATE, THE NUMBER OF UNPAIRED ELECTRONS IS THE MAXIMUM POSSIBLE AND THESE UNPAIRED ELECTRO
BartSMP [9]

Answer:

Hund's rule

Explanation:

Hund's rule  states that for an atom in the ground state, the number of unpaired electrons is the maximum possible and these unpaired electrons have the same spin.

I will clearly illustrate this using the ground state of the nitrogen atom. Nitrogen atom contains seven electrons. Its electronic configuration is; 1s2 2s2 2px1 2py1 2pz1.

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4 0
2 years ago
A solution is made by mixing equal masses of methanol, CH 4 O , and ethanol, C 2 H 6 O . Determine the mole fraction of each com
Fynjy0 [20]

Answer:

Mole fraction of CH_4O = 0.58

Mole fraction of C_2H_6O = 0.42

Explanation:

Let the mass of CH_4O and C_2H_6O = x g

Molar mass of CH_4O = 33.035 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles_{CH_4O}= \frac{x\ g}{33.035\ g/mol}

Moles_{CH_4O}=\frac{x}{33.035}\ mol

Molar mass of C_2H_6O = 46.07 g/mol

Thus,

Moles= \frac{x\ g}{46.07\ g/mol}

Moles_{C_2H_6O}=\frac{x}{46.07}\ mol

So, according to definition of mole fraction:

Mole\ fraction\ of\ CH_4O=\frac {n_{CH_4O}}{n_{CH_4O}+n_{C_2H_6O}}

Mole\ fraction\ of\ CH_4O=\frac{\frac{x}{33.035}}{\frac{x}{33.035}+\frac{x}{46.07}}=0.58

Mole fraction of C_2H_6O = 1 - 0.58 = 0.42

6 0
3 years ago
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