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3 years ago

Which of these experimental designs could lead to bias?

1 answer:

7 0

Hey there i see you need help well i am here to do just that it is c because if you are getting paid your more likely to lie ans say"great" things.
hope this helps

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Can someone help me with this molar mass problem?[It’s the last one]

quester [9]

Answer:

$54.18 \times 10^{23} \ moles$ in 3 mole of $Al_2(SO_4)_3$

Explanation:

It is clear that in the given $1\ mole$ of $Al_2(SO_4)_3$ have $3\ ions$ of $SO_4^2^-$

Therefore 3 moles of $Al_2(SO_4)_3$ will have $3\times3=9 \ ions$ of $SO_4^2^-$

Since 1 ion of anything is equivalent to $6.02\times10^{23} \ moles$

Therefore 3 moles of $Al_2(SO_4)_3$ will have $3\times3=9 \ ions$ of $SO_4^2^-$

Which is equivalent to $9 \times6.02\times10^{23}=54.18\times10^{23} \ moles$

Thus 3 moles of $Al_2(SO_4)_3$ gives $54.18\times10^{23} \ moles$ of $SO_4^2^-$ .

5 0

3 years ago

What is the pH value of Potassium hydroxide

RSB [31]

Answer:

from 10-14

Explanation:

the pH of potassium hydroxide is extremely high and is a strong base although the exact value depends on the concentration of the base in water.

3 0

1 year ago

Read 2 more answers

A sample of xenon gas occupies a volume of 6.80 L at 52.0°C and 1.05 atm. If it is desired to increase the volume of the gas sam

Pavlova-9 [17]

Answer:

207.03°C

Explanation:

The following data were obtained from the question:

V1 (initial volume) = 6.80 L

T1 (initial temperature) = 52.0°C = 52 + 273 = 325K

P1 (initial pressure) = 1.05 atm

V2 (final volume) = 7.87 L

P2 (final pressure) = 1.34 atm

T2(final temperature) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas sample can be obtained as follow:

P1V1/T1 = P2V2/T2

1.05 x 6.8/325 = 1.34 x 7.87/T2

Cross multiply to express in linear form as shown below:

1.05 x 6.8 x T2 = 325 x 1.34 x 7.87

Divide both side by 1.05 x 6.8

T2 = (325 x 1.34 x 7.87) /(1.05 x 6.8)

T2 = 480.03K

Now, let us convert 480.03K to a number in celsius scale. This is illustrated below:

°C = K - 273

°C = 480.03 - 273

°C = 207.03°C

Therefore, the final temperature of the gas will be 207.03°C

5 0

3 years ago

What is the temperature of 0.645 mole of neon in a 2.00 L vessel at 4.68 atm?

storchak [24]

Answer:

—96.03°C

Explanation:

We'll begin by writing out the information provided by the question. This includes:

Number of mole (n) = 0.645 mole

Volume (V) = 2.00 L

Pressure (P) = 4.68 atm

Temperature (T) =?

Recall: that the gas constant = 0.082atm.L/Kmol

With the ideal gas equation PV = nRT, the temperature of the gas can be obtained as follow:

PV = nRT

4.68 x 2 = 0.645 x 0.082 x T

Divide both side 0.645 x 0.082

T = (4.68 x 2) /(0.645 x 0.082)

T = 176.97 K

Now, We can also express the temperature obtained in celsius as shown below:

Temperature (celsius) = temperature (Kelvin) - 273

Temperature (celsius) = 176.97 - 273

Temperature (celsius) = —96.03°C

The temperature of the Neon gas is

—96.03°C

7 0

3 years ago

What type of effects do prostaglandins produce on smooth muscles? List two examples.

Naya [18.7K]

First, they may produce direct and relatively short-lived effects, such as stimulation of the isolated uterus or relaxation of the isolated tracheal chain preparation.

Secondly, in doses too low to produce a direct effect, they may produce a long-term potentiation of the effects of other stimulants.

3 0

3 years ago